The triangles are similar triangles, and the values of HK and GH are (b) 4 and 2√5, respectively
<h3>How to determine the length HK?</h3>
The triangles are similar triangles, and they are represented by the following similarity ratio:
GK : HK = HK : JK
From the question, we have:
GK = 2 and JK = 8
So, we have:
2 : HK = HK : 8
Express as fractions

Cross multiply
HK² = 16
Take the positive square root of both sides
HK = 4
The length GH is calculated using the following Pythagoras theorem
GH² = GK² + HK²
This gives
GH² = 2² + 4²
Evaluate the squares
GH² = 20
Solve for GH
GH = 2√5
Hence, the values of HK and GH are (b) 4 and 2√5, respectively
Read more about similar triangles at:
brainly.com/question/14285697
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Answer:
Step-by-step explanation:
Distribute the Negative Sign:
=−9x+32+−1(15x+41)
=−9x+32+−1(15x)+(−1)(41)
=−9x+32+−15x+−41
Combine Like Terms:
=−9x+32+−15x+−41
=(−9x+−15x)+(32+−41)
=−24x+−9
Answer:





Step-by-step explanation:
Given the function

Putting x=0 in the equation to find f(0)


Putting x=1 in the equation to find f(1)


Putting x=2 in the equation to find f(2)


Putting x=3 in the equation to find f(3)


Putting x=4 in the equation to find f(4)


The term circular mil is common in expressing the cross sectional area of a wire. Electrical wires have very minute diameters that are often measured a thousandth of an inch. Hence, when you find the area of the circular wire, for convenience, the unit used is circular mil which is equivalent to one-thousandth of an inch.
For example, a wire has a diameter of 6×10⁻⁵ inches. To find its area:
A = πr² = π( 6×10⁻⁵ /2)² = 2.83×10⁻⁹ in²
Since 1 mil = 1/1000 (inch) or 0.001 inch
A = (2.83×10⁻⁹ in²)* (1 mil/ 0.001 inch)²
A = 0.00283 circular mils
Answer:
320 inches
Step-by-step explanation:
First, split the figures into 2. 1 short rectangle and long rectangle.
Find the area of the longer rectangle first.
Length = 16 + 8 = 24 in
Breadth = 16 - 8 = 8 in
Formula for area of rectangle = Length x Breadth
24 in x 8 in = 192 in (Area of long rectangle)
Find the area of the short rectangle.
Breadth = 16 - 8 = 8 in
16 x 8 = 128 in (Area of short rectangle)
Since they're combined,
192 + 128 = 320
I don't know if this is correct, but I hope it was helpful)