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Alisiya [41]
3 years ago
14

Solve this equation(15x^3- 2)^3= 2197

Mathematics
1 answer:
aliya0001 [1]3 years ago
5 0

Answer:

x=1

Step-by-step explanation:

(15x^3- 2)^3= 2197

Take the cube root of each side

(15x^3- 2)^3 ^ 1/3= 2197^ 1/3

15x -2 = 13

Add 2 to each side

15x^3- 2+2= 13+2

15x^3 =15

Divide each side by 15

15x^3 /15 =15/15

x^3 =1

Take the cube root of each side

x^3 ^1/3 = 1^1/3

x=1

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The office manager of a small office ordered 140 packs of printer paper based on average daily use, she knows that the paper wil
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slope intercept form is y=mx+b

So slope intercept form is The office manager of a small office ordered 140 packs of printer paper based on average daily use, she knows that the paper will last about 80 days

(A) Lets make a table

X axis represents the Number of days paper used

y axis represents the packs of printer paper used

x            y

days      packs of printer paper used

0            0               (0 days , 0 packs used)

80          140           (in 80 days , 140 packs paper used)

The graph is attached below

(B) To find Equation of a line we use points (0,0)  and (80,140)

slope = \frac{y_2-y_1}{x_2-x_1} = \frac{140-0}{80-0} = \frac{7}{4}

y intecept is (0,0)

so b= 4

Slope intercept form of a line i y=mx + b

m is the slope and b is the y intercept

So slope intercept form of line becomes

y= \frac{7}{4} x

Standard form is Ax + By =C

y= \frac{7}{4} x

Multiply both sides by 4

4y = 7x

Now subtract 7x on both sides

-7x + 4y =0 is the standard form

(c) To find packs of printer paper  the manager expect to have after 30 days, Plug in 30 for x  and find out y

y= \frac{7}{4} x

y= \frac{7}{4}(30)= 52.5

Total 140 packs of printer paper

52.5 packs of paper used

Packs of paper remaining after 30 days = 140- 52.5= 87.5


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2 years ago
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Use the function f(x)=-1|x-4|+3 and an initial value of 1.5. Find the last two iterations and make sure that you show all your w
dezoksy [38]

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Answer:

  • f²(1.5) = -0.5
  • f³(1.5) = -1.5

Step-by-step explanation:

  f^2(1.5)=f(f(1.5)) = -1|0.5 -4|+3\\\\=-1|-3.5|+3\\\\=-1(3.5)+3\\\\=\boxed{-0.5}\\\\f^3(1.5)=f(f^2(1.5))=-1|-0.5-4|+3\\\\=-1|-4.5|+3\\\\=-1(4.5)+3\\\\=\boxed{-1.5}

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2 years ago
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