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rosijanka [135]
2 years ago
14

The measure of angle 4 is 120°, and the measure of angle 2 is 35°. What is the measure of angle 5?

Mathematics
2 answers:
pickupchik [31]2 years ago
8 0

If this was a triangle, the answer would be 35 degrees. Can you plz show a graph if you have one though?

Alenkasestr [34]2 years ago
3 0

Answer:

Option (A) is correct.

Step-by-step explanation:

In the given figure, we have

m∠4 = 120° and m∠2 = 35°.

We are to find the measure of ∠5.

Since ∠3 and ∠4 makes a linear pair, so

The sum of the measures of three angles of a triangle is 180°, so

Again, since ∠1 and ∠5 makes a linear pair, so

Thus, the measure of ∠5 is 95°.

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2 years ago
Prove that $5^{3^n} + 1$ is divisible by $3^{n + 1}$ for all nonnegative integers $n.$
Viktor [21]

When n=0, we have

5^{3^0} + 1 = 5^1 + 1 = 6

3^{0 + 1} = 3^1 = 3

and of course 3 | 6. ("3 divides 6", in case the notation is unfamiliar.)

Suppose this is true for n=k, that

3^{k + 1} \mid 5^{3^k} + 1

Now for n=k+1, we have

5^{3^{k+1}} + 1 = 5^{3^k \times 3} + 1 \\\\ ~~~~~~~~~~~~~ = \left(5^{3^k}\right)^3 + 1^3 \\\\ ~~~~~~~~~~~~~ = \left(5^{3^k} + 1\right) \left(\left(5^{3^k}\right)^2 - 5^{3^k} + 1\right)

so we know the left side is at least divisible by 3^{k+1} by our assumption.

It remains to show that

3 \mid \left(5^{3^k}\right)^2 - 5^{3^k} + 1

which is easily done with Fermat's little theorem. It says

a^p \equiv a \pmod p

where p is prime and a is any integer. Then for any positive integer x,

5^3 \equiv 5 \pmod 3 \implies (5^3)^x \equiv 5^x \pmod 3

Furthermore,

5^{3^k} \equiv 5^{3\times3^{k-1}} \equiv \left(5^{3^{k-1}}\right)^3 \equiv 5^{3^{k-1}} \pmod 3

which goes all the way down to

5^{3^k} \equiv 5 \pmod 3

So, we find that

\left(5^{3^k}\right)^2 - 5^{3^k} + 1 \equiv 5^2 - 5 + 1 \equiv 21 \equiv 0 \pmod3

QED

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1 year ago
What is the domain of this graph?
jolli1 [7]

Answer:

B 0 ≤x≤9

Step-by-step explanation:

The domain is the input values of the graph.  In this graph it is the values that the time variable takes.

Time can take 0 seconds to 9 seconds

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