If you think of the "for every" as a : then it will make sense. So, replace the "for every" with a :.
So:
There are 5 strawberries for every 6 apples
Turns into
strawberries:apples = 5:6
First, convert into a decimal:
1/10,000,000 = 0.00000001
Next, convert to "the number with a power of 10 using a negative exponent. Move the decimal point to the first <em>number that is not 0</em> (sorry, there is a term for it, but i can't remember it right now, but it is not important to solving the answer)
0.000001 = 1 * 10^-7
1 * 10^-7 is your answer
~
Answer:
80°
Step-by-step explanation:
Let the angle be x then four times it's complement plus 60, that is
4(90 - x) + 60 ← is it's supplement
Supplementary angles sum to 180°
Sum the angle and it's supplement and equate to 180
x + 4(90 - x) + 60 = 180 ← distribute and simplify left side
x + 360 - 4x + 60 = 180
- 3x + 420 = 180 ( subtract 420 from both sides )
- 3x = - 240 ( divide both sides by - 3 )
x = 80
The required angle = x = 80°
supplement = 4(90 - 80) + 60 = 4 × 10 + 60 = 40 + 60 = 100°
Answer:
![\large\boxed{x\leq-27}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7Bx%5Cleq-27%7D)
Step-by-step explanation:
![\dfrac{x}{-9}\geq3\qquad\text{change the signs}\\\\\dfrac{x}{9}\leq-3\qquad\text{multiply both sides by 9}\\\\9\!\!\!\!\diagup^1\cdot\dfrac{x}{9\!\!\!\!\diagup_1}\leq(-3)(9)\\\\x\leq-27](https://tex.z-dn.net/?f=%5Cdfrac%7Bx%7D%7B-9%7D%5Cgeq3%5Cqquad%5Ctext%7Bchange%20the%20signs%7D%5C%5C%5C%5C%5Cdfrac%7Bx%7D%7B9%7D%5Cleq-3%5Cqquad%5Ctext%7Bmultiply%20both%20sides%20by%209%7D%5C%5C%5C%5C9%5C%21%5C%21%5C%21%5C%21%5Cdiagup%5E1%5Ccdot%5Cdfrac%7Bx%7D%7B9%5C%21%5C%21%5C%21%5C%21%5Cdiagup_1%7D%5Cleq%28-3%29%289%29%5C%5C%5C%5Cx%5Cleq-27)
Answer:
![1.012 \times {10}^{ - 4}](https://tex.z-dn.net/?f=1.012%20%5Ctimes%20%7B10%7D%5E%7B%20-%204%7D%20)
Step-by-step explanation:
move the decimal so there is one non-zero digit to the left of the decimal point. the number of decimal places you move will be the exponent on the 10. if the decimal is being moved to the right, the exponent will be negative. if the decimal is being moved to the left, the exponent will be positive.