Jason's scores : 80 90 95 85 70 and
Jill's score : 70 75 90 100 95.
Mean of Jason's scores = 
Mean of Jill's scores = 
Now, in order to find the mean absolute deviation, need to find the difference of each score from means.
<u>Mean absolute deviation for Jason's scores.</u>
|84-80| = 4
|84-90| = 6
|84-95| = 9
|84-85| = 1
|84-70|= 14

<u>Mean absolute deviation for Jill's scores</u>
|86-70| = 16
|86-75| = 11
|86-90| = 4
|86-100| = 14
|86-95|= 9

Jill got average quiz score 86 and Jason got 84.
Therefore, Jill got better quiz average.
Also, the mean absolute deviation for Jason scores is less that is 6.8 than 10.8.
Therefore, Jason got more consistent grades.
The awnser is 7.47 you move the decimal over 4 spaces
Answer:
b^2√30b
Step-by-step explanation:
√30b^5 - Original
Break down the radical with its factors (factor tree)
√3*2*5*b*b*b*b*b
See what perfect squares you can take out (Can take out four b terms) You cant take out any perfect squares involving 30 since there are no perfect squares
b^2√3*2*5*b
b^2√30b
Answer:
TRUE
Step-by-step explanation:
TRUE
a_1 = 2
a_n = 2*(an_1)
if we start with 2, we would get
a_2 = 2*(a_1) = 2*(2) = 4
a_3 = 2*(a_2) = 2*(4) = 8
a_4 = 2*(a_3) = 2*(8) = 16
a_5 = 2*(a_4) = 2*(16) = 32
.
.
.
and so on
<span> Move to the right side of the </span>equation<span> by adding to both sides.</span>