This is a binomial distribution with n = 5, p = 0.55, q = 1 - 0.55 = 0.45, x = 0, 1, 2, 3
P(x) = nCx p^x q^(n - x)
P(x ≤ 3) = 1 - P(x > 3) = 1 - [P(4) + P(5)]
P(4) = 5C4 x (0.55)^4 x (0.45) = 0.2059
P(5) = 5C5 x (0.55)^5 x 1 = 0.0503
P(x ≤ 3) = 1 - (0.2059 + 0.0503) = 1 - 0.2562 = 0.7438
According to the characteristics of <em>ticket</em> sales and the resulting system of linear equations we find that 122 children bought each one a ticket on Sunday.
<h3>How many children went to the movie theatre?</h3>
In this question we have a <em>word</em> problem, whose information must be translated into <em>algebraic</em> expressions to find a solution. Let be x and y the number of children and adults that went to the movie theatre, respectively.
We need two <em>linear</em> equations, one for the number of people assisting to the theatre and another for the total sales:
x - 4 · y = 0 (1)
6.30 · x + 9.50 · y = 1063.20 (2)
By algebraic procedures the solution to this system is: x = 122.559, y = 30.639. Since the number of tickets sold are integers, then we truncate each result: x = 122, y = 30.
According to the characteristics of <em>ticket</em> sales and the resulting system of linear equations we find that 122 children bought each one a ticket on Sunday.
To learn on systems of linear equations: brainly.com/question/27664510
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Hello,
center (-9,-5)
Radius=√64=8
Answer A
Answer:
Step-by-step explanation:
m∠1 = 2x and m∠2 = -3x+235
angle 1 and angle 2 are supplementary angle so they add up to 180°
m∠1 +m∠2 = 180°
2x -3x+235 = 180°
-x = 180-235
x=35
m∠1 = 2x = 2*35 = 70°
m∠2 = -3x+235 = -3*35 +235 = 235-105 = 130°
Answer:
It can be modeled with the equation 
but needs a starting population number to finish.
Step-by-step explanation:
To find the population in a future year, use the formula:
where A is the amount, p is the starting population, r is 2% or 0.02, and t is the number of years.
Since the population is increasing it is addition. Substitute r=0.02 and t=6. Without a starting population, we cannot find the population in 6 years.
