Ok, I'm going to start off saying there is probably an easier way of doing this that's right in front of my face, but I can't see it so I'm going to use Heron's formula, which is A=√[s(s-a)(s-b)(s-c)] where A is the area, s is the semiperimeter (half of the perimeter), and a, b, and c are the side lengths.
Substitute the known values into the formula:
x√10=√{[(x+x+1+2x-1)/2][({x+x+1+2x-1}/2)-x][({x+x+1+2x-1}/2)-(x+1)][({x+x+1+2x-1}/2)-(2x-1)]}
Simplify:
<span>x√10=√{[4x/2][(4x/2)-x][(4x/2)-(x+1)][(4x/2)-(2x-1)]}</span>
<span>x√10=√[2x(2x-x)(2x-x-1)(2x-2x+1)]</span>
<span>x√10=√[2x(x)(x-1)(1)]</span>
<span>x√10=√[2x²(x-1)]</span>
<span>x√10=√(2x³-2x²)</span>
<span>10x²=2x³-2x²</span>
<span>2x³-12x²=0</span>
<span>2x²(x-6)=0</span>
<span>2x²=0 or x-6=0</span>
<span>x=0 or x=6</span>
<span>Therefore, x=6 (you can't have a length of 0).</span>
By using green to find the pink locate all the ponies
Answer:
Width = 2x²
Length = 10
Step-by-step explanation:
The greatest common monomial factor of 14x² and 6x² is 2x² so the width is 2x².
Width = 2x²
Length = (14x² ÷ 2x²) + (6x² ÷ 2x²)
= 7 + 3
= 10
Answer:
QP ≈ HG
Common side between those angles are QP and HG
so, they should be congruent to prove AAS
Answered by GAUTHMATH
Answer:
Number of catfish = 28
Step-by-step explanation:
Let the number of catfish = c
Number of angle fish = c + 6
Number of guppies = 4*(c + 6) = 4c + 4*6 = 4c + 24
Total fishes = 198
c + c + 6 + 4c + 24 = 198 {Combine like terms}
c + c +4c + 6 + 24 = 198
6c + 30 = 198 {Subtract 30 from both sides}
6c = 198 - 30
6c = 168
c = 168/6 {Divide both sides by 6}
c = 28
