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saveliy_v [14]
3 years ago
9

What is the length of a side of a cube with a volume of 216 in3? inches

Mathematics
1 answer:
yuradex [85]3 years ago
5 0
6 in is the length cause yhu have to multiply

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12x+16y=-15 in slope intercept form ? please help
Firlakuza [10]

Answer: y = -3/4x - 15/16

Step-by-step explanation: Write in slope-intercept form, y=mx+b.

Hope this helps you out! ☺

6 0
3 years ago
A survey of 1,000 men and women asked, "Do you earn over $50,000 per year?" The table below shows the responses for males and fe
Effectus [21]

Based on the data, it is found that "being female" and "earning over $50,000" are not independent events. the correct answer is option D.

<h3>What is probability?</h3>

Probability is defined as the ratio of the number of favorable outcomes to the total number of outcomes in other words the probability is the number that shows the happening of the event.

Two events, A and B are independent, if:

P(A \cap B) = P(A) P(B)

In this problem, the events are:

  • Event A: Being female.
  • Event B: Earning over $50,000.

Out of the 1000 people, 450 are female, hence:

P(A) = \dfrac{450}{1000} = 0.45

850 earn over $50,000, hence:

P(B) = \dfrac{850}{1000} = 0.85

375 are women who earn over $50,000, hence:

P(A \cap B)  = \dfrac{375}{1000} = 0.375

The multiplication of the probabilities is:

P(A \cap B)  = 0.45(0.85} = 0.3825

Therefore based on the data, it is found that "being female" and "earning over $50,000" are not independent events. the correct answer is option D.

To know more about probability follow

brainly.com/question/24756209

#SPJ1

3 0
2 years ago
Inequality to x2 &lt; 64
Anarel [89]
              NOT MY WORDS TAKEN FROM A SOURCE!

(x^2) <64  => (x^2) -64 < 64-64 => (x^2) - 64 < 0 64= 8^2    so    (x^2) - (8^2) < 0  To solve the inequality we first find the roots (values of x that make (x^2) - (8^2) = 0 ) Note that if we can express (x^2) - (y^2) as (x-y)* (x+y)  You can work backwards and verify this is true. so let's set (x^2) - (8^2)  equal to zero to find the roots: (x^2) - (8^2) = 0   => (x-8)*(x+8) = 0       if x-8 = 0 => x=8      and if x+8 = 0 => x=-8 So x= +/-8 are the roots of x^2) - (8^2)Now you need to pick any x values less than -8 (the smaller root) , one x value between -8 and +8 (the two roots), and one x value greater than 8 (the greater root) and see if the sign is positive or negative. 1) Let's pick -10 (which is smaller than -8). If x=-10, then (x^2) - (8^2) = 100-64 = 36>0  so it is positive
2) Let's pick 0 (which is greater than -8, larger than 8). If x=0, then (x^2) - (8^2) = 0-64 = -64 <0  so it is negative3) Let's pick +10 (which is greater than 10). If x=-10, then (x^2) - (8^2) = 100-64 = 36>0  so it is positive Since we are interested in (x^2) - 64 < 0, then x should be between -8 and positive 8. So  -8<x<8 Note: If you choose any number outside this range for x, and square it it will be greater than 64 and so it is not valid.

Hope this helped!

:)
7 0
3 years ago
A cable company charges a flat fee of $50 per month plus $8 per month for each movie channel, m, and $4 per month for each sport
PSYCHO15rus [73]
T = 12( 50 + 8m + 4s)

T = 600 + 96m + 48s
7 0
3 years ago
Read 2 more answers
Simplify
Diano4ka-milaya [45]

Answer:

\huge\boxed{\sqrt[4]{16a^{-12}}=2a^{-3}=\dfrac{2}{a^3}}

Step-by-step explanation:

16=2^4\\\\a^{-12}=a^{(-3)(4)}=\left(a^{-3}\right)^4\qquad\text{used}\ (a^n)^m=a^{nm}\\\\\sqrt[4]{16a^{-12}}=\bigg(16a^{-12}\bigg)^\frac{1}{4}\qquad\text{used}\ a^\frac{1}{n}=\sqrt[n]{a}\\\\=\bigg(2^4(a^{-3})^4\bigg)^\frac{1}{4}\qquad\text{use}\ (ab)^n=a^nb^n\\\\=\bigg(2^4\bigg)^\frac{1}{4}\bigg[(a^{-3})^4\bigg]^\frac{1}{4}\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=2^{(4)(\frac{1}{4})}(a^{-3})^{(4)(\frac{1}{4})}=2^1(a^{-3})^1=2a^{-3}\qquad\text{use}\ a^{-n}=\dfrac{1}{a^n}

=2\left(\dfrac{1}{a^3}\right)=\dfrac{2}{a^3}

5 0
4 years ago
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