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Vinil7 [7]
3 years ago
9

Find the distance between the two points on the graph.

Mathematics
1 answer:
puteri [66]3 years ago
8 0

let's take a peek at the graph, it has the points of (-5 , 3) and (-2 , -3), so then

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-5}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-3})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{[-2-(-5)]^2+[-3-3]^2}\implies d=\sqrt{(-2+5)^2+(-3-3)^2} \\\\\\ d=\sqrt{3^2+(-6)^2}\implies d=\sqrt{45}\implies d\approx 6.71

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Step by step solution :

Step  1  :

Pulling out like terms :

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Equation at the end of step  1  :

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3 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%2F7%7D%7B7%5Csqrt%7B10%7D%2F2%20%7D" id="TexFormula1" title="\frac{3/7}{7\sqrt{10}
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Rationalize the denominator by multiplying both numerator and denominator by √10:

\dfrac6{49\sqrt{10}}\times\dfrac{\sqrt{10}}{\sqrt{10}}=\dfrac{6\sqrt{10}}{49(\sqrt{10})^2}=\dfrac{6\sqrt{10}}{49\times10}=\dfrac{6\sqrt{10}}{490}

Lastly, cancel the common factor of 2 in both the numerator and denominator (which comes from 6 = 2×3 and 490 = 2×245):

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Answer:

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Step-by-step explanation:

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