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Vinil7 [7]
3 years ago
9

Find the distance between the two points on the graph.

Mathematics
1 answer:
puteri [66]3 years ago
8 0

let's take a peek at the graph, it has the points of (-5 , 3) and (-2 , -3), so then

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-5}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-3})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{[-2-(-5)]^2+[-3-3]^2}\implies d=\sqrt{(-2+5)^2+(-3-3)^2} \\\\\\ d=\sqrt{3^2+(-6)^2}\implies d=\sqrt{45}\implies d\approx 6.71

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The temperature in the late afternoon was -7.5° it dropped 5° by early evening and then dropped another 85° by midnight what was
dalvyx [7]

Step-by-step explanation:

i think you missed a decimal place for 8.5°

when temperatures drop it means minus

so

-7.5-5-8.5= -21°

6 0
3 years ago
HELP PLEASE BE QUICK
SVEN [57.7K]

Answer:

8

Step-by-step explanation:

<u>Area of a circle = πr^2</u>

64π / π = πr^2 / π

sqrt(64) = sqrt(r^2)

8 = r

Answer:  8

3 0
4 years ago
Evaluate the expression when y=6 and x = 35.<br> x-3y
vredina [299]

Answer:

17

Step-by-step explanation:

Given: y = 6; x + 35

Step 1: Equation

x - 3y            

Step 2: Substitution    

35 - 3(6)      

Step 3: Solving

35 - 18 = 17

Answer:

17

Hope This Helps :)

4 0
3 years ago
Read 2 more answers
O<br> 1) Which below graph represents direct variation?<br> GRAPH A<br> or<br> GRAPH B<br> Why?
Zina [86]

Answer:

Graph B

Step-by-step explanation:

The equation for direct variation is y=kx, with k being the slope. As you can see from the equation, there is no y-intercept. In graph A, you would add 8; therefore, it does not meet the requirements for direct variation.

4 0
3 years ago
Joe bought 5 apples and 4 bananas for $6. Dawn bought 3 apples and 6 bananas for $6.30. How much foes each apple and each banana
zepelin [54]

Answer:

Apple = $0.6

Banana = $0.75

Step-by-step explanation:

Let us represent Apple by A and Banana by B

For Joe,

5A + 4B = 6       (1)

For Dawn

3A + 6B = 6.3     (2)

To eliminate A, Multiply equation (1) by 3 and equation (2) by 5

15A + 12B = 18          (3)

15A + 30B = 31.5       (4)

subtracting equation (4) from (3)

15A - 15A +12B - 30B = 18 - 31.5

-18B = -13.5

divide through by -18

-18B/-18 = -13.5/-18

B = 0.75

substitute 0.75 in equation (1)

5A + 4B = 6

5A + 4(0.75) = 6

5A + 3 = 6

subtract 3 from both sides

5A + 3 - 3 = 6 - 3

5A = 3

divide through by 5

5A/5 = 3/5

A = 0.6

4 0
3 years ago
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