Since it says *10^5, we must multiply the number by 100,000.
To multiply a number by 100,000, move the decimal place of the original number 5 place values to the right. Fill in any necessary zero's.
Final answer: 183,000
1. Box off the squares (which you did)
2. Solve the area of the squares: (10cm x 10cm = 100cm each square)
3. Solve the area of the rectangle that is left: (you would do 40cm x 10cm since the other 10cm went with the square. The rectangle should end up to be 400cm.
4. Add the areas: 100cm + 100cm +400cm = 600cm
600cm is the answer
The explanation for this is one of my favorite pieces of mathematical reasoning. First, let's thing about distance; what's the shortest distance between two points? <em>A straight line</em>. If we just drew a straight line between A and B, though, we'd be missing a crucial element of the original problem: we also need to pass through a point on the line (the "river"). Here's where the mathemagic comes in.
If we take the point B and <em>reflect it over the line</em>, creating the point B' (see picture 1), we can draw a line straight from A to B' that passes through a point on the line. Notice the symmetry here; the distance from the intersection point to B' is<em> the same as its distance to B</em>. So, if we reflect that segment back up, we'll have a path to B, and because it came from of the line segment AB', we know that it's <em>the shortest possible distance that includes a point on the line</em>.
If we apply this same process to our picture, we see that the line segment AB' crosses the line
at the point (1, 1)
Answer: YES
<u>Step-by-step explanation:</u>
Coterminal means they are located at the same place on the Unit Circle but are n-rotations clockwise or counterclockwise.
Start with 35° and continue to subtract 360° (which is one rotation) until you reach -685° or pass it. If you reach -685°, then it is coterminal. If you pass it, then it is not coterminal.
35° - 360° = -325°
-325° - 360° = -685°
So, -685° is 2 rotations counterclockwise to 35°, which means the two angles are coterminal to each other.

$\sec x=\frac1{\cos x}$
$\therefore \cot^2x\cdot\sec^2x= \frac{\cos^2x}{\sin^2x}\frac{1}{\cos^2x}=\frac{1}{\sin^2x}$