24w+6c=$23.40
5w+2c=$6.60
So you have to find c (chips) first. You have to make the number of chips in both equations cancel each other.
-3(5w+2c)=-3($6.60)
-15w-6c=$-19.80
Then subtract to get one formula
24w + 6c = $23.40
-15w - 6c = $-19.80
9w = $3.60
w=$.40
To check your answer, find how much one bag of chips costs:
5($.40) + 2c = $6.60
$2.00 + 2c = $6.60
2c = $4.60
c=$2.30
Plug your value for one water and one bag of chips into the formula:
5($.40) + 2($2.30)
$2.00 + $4.60
=$6.60
Then plug your values into the original problem:
24($.40) + 6($2.30)
$9.60 + $13.80
=$23.40
Answer:
D, John did not make a mistake!
Step-by-step explanation:
Answer:
−
1
(
3
2
−
6
+
1
1
)
Step-by-step explanation:
Answer:
2x^3 + 3x^2 - 11x - 6.
Step-by-step explanation:
(2x+1) (x-2) (x+3)
= (2x + 1)[x(x + 3)-2(x + 3)]
= (2x + 1)(x^2 + x - 6)
= 2x(x^2 + x - 6) + 1(x^2 + x - 6)
= 2x^3 + 2x^2 - 12x + x^2 + x - 6
= 2x^3 + 3x^2 - 11x - 6.
