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zimovet [89]
3 years ago
9

Please anyone help i really need help it’s due please!!

Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
6 0
Answer: w = 41

QU = 2(RT)

w + 41 = 2w
w = 41
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1. Delia purchased a new car for $23,350. This make and model straight line depreciates to zero after 13 years.
frosja888 [35]

Answer:

a. y-intercept = 23350 and x-intercept = 13

b. m = -\frac{23350}{13}

c. y = -\frac{23350}{13}x + 23350

Step-by-step explanation:

Given

Years = 13

Total\ depreciation = \$23350

Solving (a): The x and y intercepts

The y intercept is the initial depreciation value

i.e. when x = 0

This value is the value of the car when it was initially purchased.

Hence, the y-intercept = 23350

The x intercept is the year it takes to finish depreciating

i.e. when y = 0

From the question, we understand that it takes 13 years for the car to totally get depreciated.

Hence, the x-intercept = 13

Solving (b): The slope

The slope (m) is the rate of depreciation per year

This is calculated by dividing the total depreciation by the duration.

So:

m = \frac{23350}{13}

Because it is depreciation, it means the slope represents a deduction.

So,

m = -\frac{23350}{13}

Solving (c): The straight line equation

The general format of an equation is:

y = mx + b

Where

m = slope

b = y\ intercept

In (a), we have that:

y\ intercept = 23350

In (b), we have that:

Slope\ (m) = -\frac{23350}{13}

Substitute these values in y = mx + b

y = -\frac{23350}{13}x + 23350

<em>Hence, the depreciation equation is: </em>y = -\frac{23350}{13}x + 23350<em></em>

8 0
2 years ago
X + 11 &lt; 6 <br> Solve and graph on a number line
Drupady [299]

Answer & Step-by-step explanation:

So I can't exactly graph exactly, but I'll try...

To solve:

x+11<6  Subtract 11 on both sides.

x<-5

To graph:

<-------|---------o---------|-------->

        -6        -5         -4

(The bolded part of the line is the side you shade the graph on. In case you can't see it, you have to shade the left side of the open circle.)

Hope this helps! Have an awesome day ( • ω • )^

4 0
2 years ago
A parallelogram- shaped tile has an area of 48 inches.2.the base of the Taiyo measures 12 inches. What is the measure of its hei
guapka [62]
Hello there,

So to find the area of anything, it's b x h and if the base of the tile is 12 you just divide 48 by 12.

48/12= 4

So the height of the tile is 4 inches

Hope this helped you!
4 0
3 years ago
I need help on everything on 45 45 90 right triangles. I dont know how to solve two variables when one is shown.
Ulleksa [173]
You can use a square plus b square equal C square to fijd each length . or you can memorize the special triangles or you can also do proportional problem. it all works
4 0
3 years ago
A circle has the equation 2x²+12x+2y²−16y−150=0.
KonstantinChe [14]

Answer: B. The coordinates of the center are (-3,4), and the length of the radius is 10 units.

Step-by-step explanation:

The equation of a circle in the center-radius form is:

(x-h)^{2} +(y-k)^{2}=r^{2} (1)

Where (h,k) are the coordinates of the center and r is the radius.

Now, we are given the equation of this circle as follows:

2x^{2}+12x+2y^{2}-16y-150=0 (2)

And we have to write it in the format of equation (1). So, let's begin by applying common factor 2 in the left side of the equation:

2(x^{2}+6x+y^{2}-8y-75)=0 (3)

Rearranging the equation:

x^{2}+6x+y^{2}-8y=75 (4)

(x^{2}+6x)+(y^{2}-8y)=75 (5)

Now we have to complete the square in both parenthesis, in order to have a perfect square trinomial in the form of (a\pm b)^{2}=a^{2}\pm+2ab+b^{2}:

<u>For the first parenthesis:</u>

x^{2}+6x+b^{2}

We can rewrite this as:

x^{2}+2(3)x+b^{2}

Hence in this case b=3 and b^{2}=9:

x^{2}+2(3)x+3^{2}=x^{2}+6x+9=(x+3)^{2}

<u>For the second parenthesis:</u>

y^{2}-8y+b^{2}

We can rewrite this as:

y^{2}-2(4)y+b^{2}

Hence in this case b=-3 and b^{2}=9:

y^{2}-2(4)y+4^{2}=y^{2}-8y+16=(y-4)^{2}

Then, equation (5) is rewritten as follows:

(x^{2}+6x+9)+(y^{2}-8y+16)=75+9+16 (6)

<u>Note we are adding 9 and 16 in both sides of the equation in order to keep the equality.</u>

Rearranging:

(x-3)^{2}+(y-4)^{2}=100 (7)

At this point we have the circle equation in the center radius form (x-h)^{2} +(y-k)^{2}=r^{2}

Hence:

h=-3

k=4

r=\sqrt{100}=10

8 0
3 years ago
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