This Question has mistakes.Correct question is
An undamped oscillator has period τo=1.000s
, but I now add a little damping so that its period changes to τ1=1.001s.
What is the damping factor β? By what factor will the amplitude of oscillation decrease after 10 cycles? Which effect of damping would be more noticeable, the change of period or the decrease of the amplitude?
Answer:
β=0.28 /sec
Amplitude=0.0606
Explanation:
Evaporation is the process of converting a liquid into vapour in chemistry. The intermolecular force is required to prevent oil from evaporating at room temperature, as stated in the above sentence, Those preventing oil from evaporating at normal temperature.
<h3>What exactly is intermolecular force?</h3>
Intermolecular forces (IMF) are the attracting and repulsive forces that exist between a substance's molecules. These forces function as a bridge between individual molecules of a substance. An intermolecular force is an attractive force that exists between the positive (or protons) components of one molecule and the negative (or electrons) components of another molecule. This force influences the physical and chemical properties of a substance. The boiling point of a substance is proportional to the strength of its intermolecular forces; the higher the boiling point, the stronger the intermolecular forces. We can compare the strengths of intermolecular forces by comparing the boiling points of different substances.
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Answer:
A. 10 N
B. 20 N
C. 1,000 N
Explanation:
D. According to Newton's Third Law, in the simplest terms, each and every action (force) has an equal but opposite reaction. So when the air pushes out to the left, the pressure of the air being released propels the balloon to the right. Therefore, Newton's Third Law is followed in this scenario. That is the same case for the above three questions as well.
Answer:
A) 1.2
B) 1.1
Explanation:
A)
F = force required to start the box moving = 36.0 N
m = mass of the box = 3 kg
= weight of the box = mg = 3 x 9.8 = 29.4 N
= normal force acting on the box by the floor
normal force acting on the box by the floor is given as
= = 29.4
= Static frictional force = F = 36.0 N
= Coefficient of static friction
Static frictional force is given as
=
36.0 = (29.4)
= 1.2
B)
a = acceleration of the box = 0.54 m/s²
F = force applied = 36.0 N
= kinetic frictional force
= Coefficient of kinetic friction
force equation for the motion of the box is given as
F - = ma
36.0 - = (3) (0.54)
= 34.38 N
Coefficient of kinetic friction is given as
= 1.1