I assume the block plows into the bank of sand with a velocity of 6 m/s and comes to a stop in 2 s.
Answer:
angular range is ( 0.681 rad , 0.35 rad )
Explanation:
given data
wavelength λ = 380 nm = 380 × m
wavelength λ = 700 nm = 700 × m
to find out
angular range of the first-order
solution
we will apply here slit experiment equation that is
d sinθ = m λ ...........1
here m is 1 for single slit and d is =
so put here value in equation 1 for 380 nm
we get
d sinθ = m λ
sinθ = 1 × 380 ×
θ = 0.35 rad
and for 700 nm
we get
d sinθ = m λ
sinθ = 1 × 700 ×
θ = 0.681 rad
so angular range is ( 0.681 rad , 0.35 rad )
What are your answer choices?
<span>A center-seeking force related to acceleration is centripetal force. The answer is letter A. The rest of the choices do not answer the question above.</span>
Answer:
The width of the central bright fringe is 7.24 mm.
Explanation:
Given that,
Wavelength = 632.8 nm
Width d= 0.350 mm
Distance between screen and slit D= 2.00 m
We need to calculate the distance
Using formula of distance
Put the value into the formula
We need to calculate the width of the central bright fringe
Using formula of width
Put the value into the formula
Hence, The width of the central bright fringe is 7.24 mm.