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bagirrra123 [75]
3 years ago
6

Using the linear equation 3x+2y=6, express y in terms of x

Mathematics
2 answers:
wolverine [178]3 years ago
7 0

Answer: any number

Step-by-step explanation: 3x+2y=6, 2y=6-3x, we want y by itself, so divide by 2 from both sides, y=3-1.5x, then we plug it into the equation,3x+2(3-1.5)=6, then solve. 3x+6-3x=6, 3x-3x=0,so 6=6, y could be any possible answer

omeli [17]3 years ago
3 0

y =   \frac{ - 3}{2} x + 3

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Two cyclists, Alan and Brian, are racing around oval track of length 450m on the same direction simultaneously from the same poi
skelet666 [1.2K]

Answer:

Alan: 200 m/min

Brian: 150 m/min

Step-by-step explanation:    

Given : Two cyclists, Alan and Brian, are racing around oval track of length 450m on the same direction simultaneously from the same point. Alan races around the track in 45 seconds before Brian does and overtakes him every 9 minutes.

To find : What are their rates, in meters per minute?

Solution :

Let n represent the number of laps that Alan completes in 9 minutes.

Then n-1 is the number of laps Brian completes.

45 seconds = 3/4 minutes.

The difference in their lap times in minutes per lap is

\frac{9}{(n -1)}-\frac{9}{n} =\frac{3}{4}

Solving the equation we get,

\frac{9n-9n+9}{n(n -1)} =\frac{3}{4}

9\times 4=3\times n(n -1)

36=3\times n(n -1)

n^2-n-12=0

n^2-4n+3n-12=0

n(n-4)+3(n-4)=0

(n-4)(n+3)=0

n=4,-3

Neglecting n=-3

So, n=4

Then Alan's speed in m/min is

S=\frac{D}{T}

S_a=\frac{4\times 450}{9}

S_a=200 m/min

Brian completes 3 laps in that 9-minute time, so his rate is

S_b=\frac{3\times 450}{9}

S_b=150 m/min

Therefore, Alan: 200 m/min

Brian: 150 m/min

4 0
3 years ago
Match the features of the graph of the rational function.
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After applying <em>algebraic</em> analysis we find the <em>right</em> choices for each case, all of which cannot be presented herein due to <em>length</em> restrictions. Please read explanation below.

<h3>How to analyze rational functions</h3>

In this problem we have a rational function, whose features can be inferred by algebraic handling:

Holes - x-values that do not belong to the domain of the <em>rational</em> function:

x³ + 8 · x² - 9 · x = 0

x · (x² + 8 · x - 9) = 0

x · (x + 9) · (x - 1) = 0

x = 0 ∨ x = - 9 ∨ x = 1

But one root is an evitable discontinuity as:

y = (9 · x² + 81 · x)/(x³ + 8 · x² - 9 · x)

y = (9 · x + 81)/(x² + 8 · x - 9)

Thus, there are only two holes. (x = - 9 ∨ x = 1) Besides, there is no hole where the y-intercept should be.

Vertical asymptotes - There is a <em>vertical</em> asymptote where a hole exists. Hence, the function has two vertical asymptotes.

Horizontal asymptotes - <em>Horizontal</em> asymptote exists and represents the <em>end</em> behavior of the function if and only if the grade of the numerator is not greater than the grade of the denominator. If possible, this assymptote is found by this limit:

y = \lim_{x \to \pm \infty} \frac {9\cdot x + 81}{x^{2}+8\cdot x - 9}

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The function has a horizontal asymptote.

x-Intercept - There is an x-intercept for all x-value such that numerator is equal to zero:

9 · x + 81 = 0

x = - 9

There is a x-intercept.

Lastly, we have the following conclusions:

  1. How many holes? 2
  2. One <em>horizontal</em> asymptote along the line where y always equals what number: 0
  3. This function has x-intercepts? True
  4. One <em>vertical</em> asymptote along the line where x always equals what number: 1
  5. There is a hole where the y-intercept should be? False

To learn more on rational functions: brainly.com/question/27914791

#SPJ1

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