end behavior is affect by the exponent and whether its negative or positive
y = y^3 starts negative from -∞ to 0 the from 0 to +∞ goes positive
since this equation is negative its switched
-∞ to 0 its positive x>0
0 to +∞ is negative x<0
Let's solve for x.
5x+15y=12
Step 1: Add -15y to both sides.
5x+15y+−15y=12+−15y
5x=−15y+12
Step 2: Divide both sides by 5.
5x
5
=
−15y+12
5
x=−3y+
12
5
Answer:
x=−3y+12/5
Let's solve for y.
5x+15y=12
Step 1: Add -5x to both sides.
5x+15y+−5x=12+−5x
15y=−5x+12
Step 2: Divide both sides by 15.
15y
15
=
−5x+12
15
y=
−1
3
x+
4
5
Answer:
y=-1/3x+4/5
Hope this helps!
-Josh
brainliest?
Answer: 5.4
Step-by-step explanation:
The independent variable (the one they want) is the # of hours worked, since that determines the price.
All the other answers contain information not included in the problem
<h3>
Answer: 0.5</h3>
This is equivalent to the fraction 1/2
==============================================================
Explanation:
The distance from A to B is 3 units. We can count out the spaces, or subtract the x coordinates of the two points and apply absolute value.
|A-B| = |-5-(-8)| = |-5+8| = |3| = 3
or
|B-A| = |-8-(-5)| = |-8+5| = |-3| = 3
We can say that segment AB is 3 units long.
--------------------------
The distance from A' to B' is 1.5 units because...
|A'-B'| = |-2.5-(-4)| = |-2.5+4| = |1.5| = 1.5
or
|B'-A'| = |-4-(-2.5)| = |-4+2.5| = |-1.5| = 1.5
The absolute values ensure the distance is never negative.
We can say A'B' = 1.5
---------------------------
Now divide the lengths of A'B' over AB to get the scale factor k
k = (A'B')/(AB)
k = (1.5)/(3)
k = 0.5
0.5 converts to the fraction 1/2.
The smaller rectangle A'B'C'D' has side lengths that are exactly 1/2 as long compared to the side lengths of ABCD.
