If the discriminant of a quadratic equation is positive, which of the following is true of the equation?

Mathematics

2 answers:

gregori [183]3 years ago

6 0

Answer:

it is b. it has two real solutions.

Step-by-step explanation:

Yanka [14]3 years ago

3 0

For this case suppose that we have a quadratic equation of the form:
$ax ^ 2 + bx + c
$
The solution to the quadratic recuacion is given by:
$x = \frac{-b +/- \sqrt{b^2 - 4ac}}{2a}$
Where,
The discriminant is:
$b ^ 2 - 4ac
$
When the discriminant is greater than zero, then the root is positive, and therefore, we have two positive real solutions.
Answer:
B. it has two real solutions

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liq [111]

By right triangle trigonometry, the sine of the measure of an angle is the ratio of the opposite side of this angle to the hypotenuse.

Thus, $\displaystyle{\sin27^{\circ}= \frac{34}{x}$

$\sin27^{\circ}$ is a constant which can be found using a calculator:

with calc in pc: view → scientific → 27→sin = 0.45399,

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5 0

2 years ago

You pick a card at random from an ordinary deck of 52 cards. If the card is an ace, you get 9 points; if not, you lose 1 point.

Andreyy89

Answer:

$a = 9\\b = 48\\c = -1$

Step-by-step explanation:

We know that:

In a deck of 52 cards there are 4 aces.

Therefore the probability of obtaining an ace is:

P (x) = 4/52

The probability of not getting an ace is:

P ('x) = 1-4 / 52

P ('x) = 48/52

In this problem the number of aces obtained when extracting cards from the deck is a discrete random variable.

For a discrete random variable V, the expected value is defined as:

$E(V) = VP(V)$

Where V is the value that the random variable can take and P (V) is the probability that it takes that value.

We have the following equation for the expected value:

$E(V) = \frac{4}{52}(a) + \frac{b}{52}(c)$

In this problem the variable V can take the value V = 9 if an ace of the deck is obtained, with probability of 4/52, and can take the value V = -1 if an ace of the deck is not obtained, with a probability of 48 / 52

Therefore, expected value for V, the number of points obtained in the game is:

$E(V) = \frac{4}{52}(9) + \frac{48}{52}(-1)$