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Vladimir79 [104]
3 years ago
5

a large container holds 5 gallons of water. it begins leaking at a constant rate. after 15 minutes, the container has 2 gallons

of water left. at what rate is the water leaking?
Mathematics
1 answer:
Scrat [10]3 years ago
8 0

Answer:

1 gallon ever 5 minutes here is the fraction form if you need it for a graph 3/15 or 1/5

Step-by-step explanation:

if there is 3 gallons gone and it is constant then on gallon goes every 5 minutes 15/3=5

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Janet has a square piece of cloth. She cuts 3 inches off of the length of the square and 3 inches off of the width. The area of
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24
3+3=6
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24 inches
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3 years ago
Find the p-value: An independent random sample is selected from an approximately normal population with an unknown standard devi
vladimir1956 [14]

Answer:

(a) <em>p</em>-value = 0.043. Null hypothesis is rejected.

(b) <em>p</em>-value = 0.001. Null hypothesis is rejected.

(c) <em>p</em>-value = 0.444. Null hypothesis is not rejected.

(d) <em>p</em>-value = 0.022. Null hypothesis is rejected.

Step-by-step explanation:

To test for the significance of the population mean from a Normal population with unknown population standard deviation a <em>t</em>-test for single mean is used.

The significance level for the test is <em>α</em> = 0.05.

The decision rule is:

If the <em>p - </em>value is less than the significance level then the null hypothesis will be rejected. And if the <em>p</em>-value is more than the value of <em>α</em> then the null hypothesis will not be rejected.

(a)

The alternate hypothesis is:

<em>Hₐ</em>: <em>μ</em> > <em>μ₀</em>

The sample size is, <em>n</em> = 11.

The test statistic value is, <em>t</em> = 1.91 ≈ 1.90.

The degrees of freedom is, (<em>n</em> - 1) = 11 - 1 = 10.

Use a <em>t</em>-table t compute the <em>p</em>-value.

For the test statistic value of 1.90 and degrees of freedom 10 the <em>p</em>-value is:

The <em>p</em>-value is:

P (t₁₀ > 1.91) = 0.043.

The <em>p</em>-value = 0.043 < <em>α</em> = 0.05.

The null hypothesis is rejected at 5% level of significance.

(b)

The alternate hypothesis is:

<em>Hₐ</em>: <em>μ</em> < <em>μ₀</em>

The sample size is, <em>n</em> = 17.

The test statistic value is, <em>t</em> = -3.45 ≈ 3.50.

The degrees of freedom is, (<em>n</em> - 1) = 17 - 1 = 16.

Use a <em>t</em>-table t compute the <em>p</em>-value.

For the test statistic value of -3.50 and degrees of freedom 16 the <em>p</em>-value is:

The <em>p</em>-value is:

P (t₁₆ < -3.50) = P (t₁₆ > 3.50) = 0.001.

The <em>p</em>-value = 0.001 < <em>α</em> = 0.05.

The null hypothesis is rejected at 5% level of significance.

(c)

The alternate hypothesis is:

<em>Hₐ</em>: <em>μ</em> ≠ <em>μ₀</em>

The sample size is, <em>n</em> = 7.

The test statistic value is, <em>t</em> = 0.83 ≈ 0.82.

The degrees of freedom is, (<em>n</em> - 1) = 7 - 1 = 6.

Use a <em>t</em>-table t compute the <em>p</em>-value.

For the test statistic value of 0.82 and degrees of freedom 6 the <em>p</em>-value is:

The <em>p</em>-value is:

P (t₆ < -0.82) + P (t₆ > 0.82) = 2 P (t₆ > 0.82) = 0.444.

The <em>p</em>-value = 0.444 > <em>α</em> = 0.05.

The null hypothesis is not rejected at 5% level of significance.

(d)

The alternate hypothesis is:

<em>Hₐ</em>: <em>μ</em> > <em>μ₀</em>

The sample size is, <em>n</em> = 28.

The test statistic value is, <em>t</em> = 2.13 ≈ 2.12.

The degrees of freedom is, (<em>n</em> - 1) = 28 - 1 = 27.

Use a <em>t</em>-table t compute the <em>p</em>-value.

For the test statistic value of 0.82 and degrees of freedom 6 the <em>p</em>-value is:

The <em>p</em>-value is:

P (t₂₇ > 2.12) = 0.022.

The <em>p</em>-value = 0.444 > <em>α</em> = 0.05.

The null hypothesis is rejected at 5% level of significance.

5 0
3 years ago
ANSWER THIS QUESTION FOR BRAINLEST AND 10 POINTS
ivolga24 [154]

Answer:

I beleive that the answer is (1,2)

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Please help im stuck on this question​
VARVARA [1.3K]

Answer:

(12,0)

Step-by-step explanation:

slope m=

\frac{54-36}{27-22} =\frac{18}{5}

y-36=\frac{18}{5}(x-22)\\\\5y-180=18x-396\\\\y=\frac{18x}{5} -\frac{46}{5}

0=\frac{10}{5}x-\frac{46}{5}\\\\x=\frac{216}{18}   =12

hope it helps...

have a great day

7 0
2 years ago
What is the inverse of the function
Evgesh-ka [11]

Answer:

A

Step-by-step explanation:

let y = f(x) and rearrange making x the subject, that is

y = \frac{19}{x^3} ( multiply both sides by x³ )

x³y = 19 ( divide both sides by y )

x³ = \frac{19}{y} ( take the cube root of both sides )

x = \sqrt[3]{\frac{19}{y} }

Change y back into terms of x, then

f^{-1} (x) = \sqrt[3]{\frac{19}{x} } = \frac{\sqrt[3]{19} }{\sqrt[3]{x} } → A

6 0
3 years ago
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