Question

a rectangle has an area of 320 feet squared. the length is 4 feet longer than the width. find the dimensions.

Answer 1

Width of the rectangle is 16 ft and length of the rectangle is 20 ft

Step-by-step explanation:

Step 1:

Given area of the rectangle = 320 ft². Let the width of the rectangle be x, then the length = x + 4. Use the formula for area of a rectangle = (length × width)

320 = x(x + 4)

320 = x² + 4x

x² + 4x - 320 = 0

x = (-b ±√b² - 4ac)/2a = (-4 ±√16 - 4×1×-320)/2

  = (-4±√1296)/2 = (-4 ± 36)/2

  = 32/2, -40/2 = 16, -20 (neglecting the negative value)

∴ Width of the rectangle = 16 ft

∴ Length of the rectangle = 16 + 4 = 20ft