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JulsSmile [24]
3 years ago
12

a rectangle has an area of 320 feet squared. the length is 4 feet longer than the width. find the dimensions.

Mathematics
1 answer:
deff fn [24]3 years ago
4 0

Width of the rectangle is 16 ft and length of the rectangle is 20 ft

<u>Step-by-step explanation:</u>

Step 1:

Given area of the rectangle = 320 ft². Let the width of the rectangle be x, then the length = x + 4. Use the formula for area of a rectangle = (length × width)

320 = x(x + 4)

320 = x² + 4x

x² + 4x - 320 = 0

x = (-b ±√b² - 4ac)/2a = (-4 ±√16 - 4×1×-320)/2

  = (-4±√1296)/2 = (-4 ± 36)/2

  = 32/2, -40/2 = 16, -20 (neglecting the negative value)

∴ Width of the rectangle = 16 ft

∴ Length of the rectangle = 16 + 4 = 20ft

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