Answer:
The probability that can afford to spend between $800 and $900
P(800≤X≤900) = 0.6826
The percentage of that can afford to spend between $800 and $900
P(800≤X≤900) = 68 percentage
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given that the mean of the Normal distribution = $850
Given that the standard deviation of the Normal distribution = $50
Let 'X' be a random variable in a normal distribution
Let x₁ = 800

Let x₂ =850

<u><em>Step(ii):-</em></u>
The probability that can afford to spend between $800 and $900
P(800≤X≤900) = P(-1≤Z≤1)
= P(Z≤1) - P(Z≤-1)
= 0.5 + A(1) - (0.5 - A(-1))
= A(1) +A(-1)
= 2× A(1) (∵ A(-1) =A(1)
= 2 × 0.3413
= 0.6826
The percentage of that can afford to spend between $800 and $900
P(800≤X≤900) = 68 percentage
Answer:
Hello
Step-by-step explanation:
2+2=22 facts lol
Answer: $91
Step-by-step explanation:
If a set of 4 tires costs $364, 1 tire cost 364/4 = $91
Answer:
option D is true.
Step-by-step explanation:
Given the sequence
7, 12, 17, 22, ...
An arithmetic sequence has a constant difference 'd' and is defined by

Computing the differences of all the adjacent terms

The difference between all the adjacent terms is the same
so

as

Thus, the nth term of the arithmetic sequence will be:


Therefore, option D is true.
The last one is rational because it is a terminating decimal.