Answer:
The probability that can afford to spend between $800 and $900
P(800≤X≤900) = 0.6826
The percentage of that can afford to spend between $800 and $900
P(800≤X≤900) = 68 percentage
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given that the mean of the Normal distribution = $850
Given that the standard deviation of the Normal distribution = $50
Let 'X' be a random variable in a normal distribution
Let x₁ = 800
Let x₂ =850
<u><em>Step(ii):-</em></u>
The probability that can afford to spend between $800 and $900
P(800≤X≤900) = P(-1≤Z≤1)
= P(Z≤1) - P(Z≤-1)
= 0.5 + A(1) - (0.5 - A(-1))
= A(1) +A(-1)
= 2× A(1) (∵ A(-1) =A(1)
= 2 × 0.3413
= 0.6826
The percentage of that can afford to spend between $800 and $900
P(800≤X≤900) = 68 percentage