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notka56 [123]
3 years ago
5

The KE of a body becomes 2 times of its original value then the new momentum will be more than its initial momentum by​

Physics
1 answer:
sladkih [1.3K]3 years ago
7 0

Answer:

√2

Explanation:

If the final kinetic energy is 2 times the initial kinetic energy:

KE = 2 KE₀

½ mv² = 2 (½ mv₀²)

v² = 2 v₀²

v = √2 v₀

Therefore, the ratio of the final momentum to the initial momentum is:

p / p₀

mv / (mv₀)

v / v₀

√2

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What is the mass of a piece of zinc that absorbs 1576 calories of heat and increased its temperature by 8.7 °C (specific heat of
Artyom0805 [142]

Answer:

m = 476.5[g].

Explanation:

In order to solve this problem, we must use the following equation of thermal energy.

Q=m*c_{p}*(T_{final}-T_{initial})

where:

Q = heat energy = 1576 [cal]

Cp = specific heat = 0.39 [cal/g*°C]

T_final = final temperature [°C]

T_initial = initial temperature [°C]

m = mass of the piece of zinc [g]

We must keep in mind that the difference of the final temperature minus the initial temperature results in the increase in temperature.

T_{final}-T_{initial} = 8.7[C]

Now replacing:

1576=m*0.39*(8.7)\\m=476.5[g]

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3 years ago
The space shuttle passes over mission control in Texas. After it flies a distance of 1,600,000 meters it is above Florida. If th
DiKsa [7]
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3 years ago
The density of water is 1000 kg m^3. What is the value expressed in gcm^-3 units? please help me..
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The answer is 1 which is option 3
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Can you have zero displacement and nonzero average velocity? Zero displacement and nonzero velocity? Illustrate your answers on
Svetlanka [38]

a) Not possible

b) Yes, it's possible (see graph in attachment)

Explanation:

a)

The average velocity of a body is defined as the ratio between the displacement and the time elapsed:

v=\frac{\Delta x}{\Delta t}

where

\Delta x is the displacement

\Delta t is the time elapsed

In this problem, we want to have zero displacement and non-zero average velocity. From the equation above, we see that this is not possible. In fact, if the total displacement is zero,

\Delta x = 0

And therefore as a consequence,

v=0

which means that the average velocity is zero.

B)

Here we want to have zero displacement and non-zero velocity. In this case, it is possible: in fact, we are not talking  about average velocity, but we are talking about (instantaneous) velocity.

On a position-time graph, the instantaneous velocity is the slope of the graph. Look at the graph in attachment. We see that the position of the object first increases towards positive value, then it decreases (the object starts moving backward), then becomes negative, then it increases again until returning to the original position, x = 0.

In all of this, we notice that the total displacement of the object is zero:

\Delta x = 0

However, we notice that the instantaneous velocity of the object at the various instants is not zero, because the slope of the graph is not zero.

Learn more about average velocity:

brainly.com/question/8893949

brainly.com/question/5063905

#LearnwithBrainly

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