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Gnoma [55]
3 years ago
5

A 3.00 kg cart on a frictionless track is pulled by a string so that it accelerates at 2.00 m/s/s. what is the tension in the st

ring'
PLEASE SHOW YOUR WORK
Physics
1 answer:
lys-0071 [83]3 years ago
3 0
The mass is m =  3kg

The acceleration is a =  2m/s/s

Force is equal to mass times acceleration

F = m*a = 3kg*2m/s/s = 6 N

This force is equal to the tension in the string

T = 6 N
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An airplane undergoes the following displacements, all at the same altitude: First, it flies 59.0 km in a direction 30.0° east o
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Answer:

B) 71.5 [km]

Explanation:

To solve this problem we will decompose each of the directions in the x & y axes.

To solve this problem we will decompose each of the directions in the x & y axes. also for a greater understanding of the angles, you should look at the attached image, which contains the orientations for each angle (clockwise or counterclockwise).

<u>59.0 km in a direction 30.0° east of north</u>

<u />

d_{1x}= 59*sin(30) = 29.5[km]\\d_{1y}= 59*cos(30) = 51.09[km]

<u>58.0 km due south</u>

<u />

d_{2y} = - 58 [km]\\

<u>It flies 100 km 30.0° north of west</u>

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<u />d_{3x}= - 100*cos(30) = -86.6[km]\\d_{3y} = 100*sin(30)= 50 [km]<u />

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Now we sum algebraically the components

d_{x}=29.5-86.6 = -57.1[km]\\d_{y}=51.09 -58+50=43.09[km]\\\\

Using the Pythagorean theorem we can find the magnitude of the displacement.

d = \sqrt{(57.1)^{2} +(43.09)^{2} } \\d= 71.53[km]

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How does sound travel through a medium?
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(pleases show work)
Feliz [49]

a. 46 m/s east

The jet here is moving with a uniform accelerated motion, so we can use the following suvat equation to find its velocity:

v=u+at

where

v is the velocity calculated at time t

u is the initial velocity

a is the acceleration

The jet in the problem has, taking east as positive direction:

u = +16 m/s  is the initial velocity

a=+3 m/s^2  is the acceleration

Substituting t = 10 s, we find the final velocity of the jet:

v=16 + (3)(10)=46 m/s

And since the result is positive, the direction is east.

b. 310 m

The displacement of the jet can be found using another suvat equation

s=ut+\frac{1}{2}at^2

where

s is the displacement

u is the initial velocity

a is the acceleration

t is the time

For the jet in this problem,

u = +16 m/s  is the initial velocity

a=+3 m/s^2  is the acceleration

t = 10 s is the time

Substituting into the equation,

s=(16)(10)+\frac{1}{2}(3)(10)^2=310 m

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Hey!

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Answer:

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