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kotegsom [21]
4 years ago
7

Part A: What is the average rate of change for h(t) between t=0 and t=2?

Mathematics
1 answer:
Kaylis [27]4 years ago
8 0
The answer to you question is idk
You might be interested in
6. Carla runs 3 miles in 30 minutes.
NARA [144]

Answer:

Carla ran 0.1 miles per minute.

Step-by-step explanation:

To solve this, we need to use the distance formula.

The formula is d=rt, where d is the distance traveled, r is the rate in which the distance is traveled, and t is the amount of time it took to go that distance. So lets plug it all in.

d=rt

3=(r)(30)

Now, we need to do the inverse of multiplying 30 to both sides, which would be the same as dividing by 30 on both sides.

3/30=(r)(30/30)

0.1=r

The rate is 0.1. Carla ran 0.1 miles per minute.

3 0
3 years ago
Identify the number of solutions:<br> 5x + 4 = 5x + 4
Murrr4er [49]

Answer:

0,4) : not a solution

(-2,4) ; solution

(0,5) : solution

(-2,7) : solution

(-4,1) : not a solution

(-1,1) : not a solution

(-1.5,3.5) : solution

any point that falls in the grey area is a solution....if ur points lie on a dashed line, it is not a solution...but if ur points lie on a solid line, it is a solution

Step-by-step explanation:

6 0
4 years ago
Explain how you could solve the following using equal groups.
nignag [31]

Answer:

6

Step-by-step explanation:

48/8=6

3 0
3 years ago
Evaluate the expression when a=−15 and b=−5. <br><br> hat would -<br> A divided by b = ? <br> be?
fiasKO [112]

Answer:

<h3>3</h3>

Step-by-step explanation:

Given the following values a=−15 and b=−5.

We are to find a/b

a/b = -15/-5

a/b = 15/3

a/b = 5*3/5*1

a/b = 5/5 * 3

a/b = 1*3

a/b = 3

Hence a divided b will be 3

8 0
3 years ago
Let n be any natural number greater than 1. Explain why the numbers n! 2, n! 3, n! 4, ..., n! n must all be composite. (This exe
bagirrra123 [75]

Answer:

Because each term of the sequence generates numbers with more than 1 and itself as dividers

Step-by-step explanation:

Just for the sake of correction.

1. Explain\: why\: the\: numbers\: n! +2, n!+ 3, n!+ 4, ..., n! \\n \:must\: all\: be\: composite.

1) Let's consider that

n! =n(n-1)(n-2)(n-3)...

2)And examine some numbers of that sequence above:

n!+2

Every Natural number plugged in n, and added by two will a be an even number not only divisible by two, but in some cases by other numbers for example,n=4, then 4!+2=26 which has four dividers.

3) Similarly, the same happens to

n!+3 and n!+4

Where we can find many dividers.

There's an example of a sequence, let's start with a prime number greater than 1

Let n=11

\left \{ n!+2,n!+3,n!+4,n!+5,n!+6,...n!+n. \right \}\\\left \{ 11!+2,11!+3,11!+4,11!+5,11!+6,11!+7,11!+8,...11!+11 \right \}\\\\

That's a long sequence of consecutive composite numbers, n=11.

\left \{39916802, 39916803,39916804,39916805,39916806,39916807,...,39916811,39916812 \right \}

4 0
4 years ago
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