Answer:
Option A) independent variable – self-affirmations; dependent variable – self-esteem scores
Step-by-step explanation:
We are given the following in the question:
"Wood and colleagues (2009) examined the value of self-affirmation. In a typical study, participants either engaged or did not engage in self-affirmations. Later, their current self-esteem was assessed."
Independent and Dependent Variable:
- Dependent variable is the variable whose value depends on the independent variable.
- Independent variable is the free variable.
For the given scenario, self esteem is assessed based on the fact that participants either engaged or did not engage in self-affirmations.
Thus, the dependent variable is self esteem and the independent variable is engagement in self affirmation.
Thus, the correct answer is
Option A) independent variable – self-affirmations; dependent variable – self-esteem scores
Answer:
1. 70 2. 85 3. 63 4. 20 5. They are vertical angles
Step-by-step explanation:

by the double angle identity for sine. Move everything to one side and factor out the cosine term.

Now the zero product property tells us that there are two cases where this is true,

In the first equation, cosine becomes zero whenever its argument is an odd integer multiple of

, so

where
![n[/tex ]is any integer.\\Meanwhile,\\[tex]10\sin x-3=0\implies\sin x=\dfrac3{10}](https://tex.z-dn.net/?f=n%5B%2Ftex%20%5Dis%20any%20integer.%5C%5CMeanwhile%2C%5C%5C%5Btex%5D10%5Csin%20x-3%3D0%5Cimplies%5Csin%20x%3D%5Cdfrac3%7B10%7D)
which occurs twice in the interval

for

and

. More generally, if you think of

as a point on the unit circle, this occurs whenever

also completes a full revolution about the origin. This means for any integer

, the general solution in this case would be

and

.