How do you determine if a pair of lines are parallel? For example, the lines -3x+8y=24 and 3x-8y=7?

1 answer:

7 0

first you put this equation into y=mx+b form then you look at the slope of the equation. if both of the slopes are same then its parallel.

You might be interested in

Can someone answer this math question please???

Lapatulllka [165]

Answer:

TOO MUCH!!!

Step-by-step explanation:

8 0

2 years ago

What is the slope of the line that passes through the points (-8, -6)(−8,−6) and (-18, 6) ?(−18,6)?

ivolga24 [154]

Answer:

Slope: $\frac{12}{10}$

8 0

2 years ago

Question 9(Multiple Choice Worth 1 points) (01.06 LC) Solve x -5y = 6 for x.

vladimir1956 [14]

The answer is x = 6 + 5y

5 0

2 years ago

Suppose a parabola has an axis of symmetry at x=-5, a maximum height of 9, and passes through the point (-7,1). Write the equati

Nutka1998 [239]

the parabola has maximum at 9, meaning is a vertical parabola and it opens downwards.

it has a symmetry at x = -5, namely its vertex's x-coordinate is -5.

check the picture below.

so then, we can pretty much tell its vertex is at (-5 , 9), and we also know it passes through (-7, 1)

$\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} y=a(x- h)^2+ k\qquad \leftarrow \textit{using this one}\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{}{ h},\stackrel{}{ k}) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=-5\\ k=9 \end{cases}\implies y=a[x-(-5)]^2+9\implies y=a(x+5)^2+9$

$\bf \textit{we also know that } \begin{cases} x=-7\\ y=1 \end{cases}\implies 1=a(-7+5)^2+9 \\\\\\ -8=a(-2)^2\implies -8=4a\implies \cfrac{-8}{4}=a\implies -2=a \\\\[-0.35em] ~\dotfill\\\\ ~\hfill y=-2(x+5)^2+9~\hfill$