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3 years ago

Can anyone help me with this?

Mathematics

1 answer:

erma4kov [3.2K]3 years ago

3 0

Answer: 16y² - x²

Step-by-step explanation: The - sign means a difference, so the choices with + signs are eliminated (though 64x² and 9 are squares)

10 is not a square so that one is eliminated (though the y² and the 4x² are squares)

16 is the square of 4, y² is the square of y, and x² is the square. That expression shows a difference of squares.

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How do you solve this system of equation? 2x+4y=-4 3x + 5y =-3

Annette [7]

Answer:

x = 4

y = -3

Step-by-step explanation:

We can use substitution, elimination, or graphically.

Step 1: Rearrange first equation

2x + 4y = -4

2x = -4 - 4y

x = -2 - 2y

Step 2: Rewrite systems of equations

x = -2 - 2y

3x + 5y = -3

Step 3: Substitution

3(-2 - 2y) + 5y = -3

-6 - 6y + 5y = -3

-6 - y = -3

-y = 3

y = -3

Step 4: Find x using y

2x + 4(-3) = -4

2x - 12 = -4

2x = 8

x = 4

Graphically:

Use a graphing calc and analyze where the 2 lines intersect.

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4 years ago

Eva sees a dolphin 3.2 meters below sea level and a bird 47/10 meters above sea level. Which of the following expressions repres

Mars2501 [29]

7.9 meters apart from each other

6 0

3 years ago

Read 2 more answers

Solve the equation for all values of x. (8x+9)(49x^2-100)=0

Liono4ka [1.6K]

Answer:

$x = \frac{-9}{8} , \frac{-10}{7} , \frac{10}{7}$

Step-by-step explanation:

8x+9=0

8x=-9

$x = \frac{-9}{8}$

$49x^{2}-100 = 0$

$(7x)^{2} -10^{2} =0$ ,

$(7x+10)(7x-10)=0$

$7x+10=0, 7x-10=0$

$7x=-10, 7x=10$

$x=-\frac{-10}{7}$ , $x = \frac{10}{7}$

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3 years ago

What is the perimeter of △RST?

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Answer:

Step-by-step explanation:

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3 years ago

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Give a 98% confidence interval for one population mean, given asample of 28 data points with sample mean 30.0 and sample standar

klio [65]

We have a sample of 28 data points. The sample mean is 30.0 and the sample standard deviation is 2.40. The confidence level required is 98%. Then, we calculate α by:

$\begin{gathered} 1-\alpha=0.98 \\ \alpha=0.02 \end{gathered}$

The confidence interval for the population mean, given the sample mean μ and the sample standard deviation σ, can be calculated as:

$CI(\mu)=\lbrack x-Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}},x+Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}}\rbrack$

Where n is the sample size, and Z is the z-score for 1 - α/2. Using the known values:

$CI(\mu)=\lbrack30.0-Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}},30.0+Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}}\rbrack$

Where (from tables):

$Z_{0.99}=2.33$

Finally, the interval at 98% confidence level is:

$CI(\mu)=\lbrack28.94,31.06\rbrack$

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1 year ago