Answer:
We can have two cases.
A quadratic function where the leading coefficient is larger than zero, in this case the arms of the graph will open up, and it will continue forever, so the maximum in this case is infinite.
A quadratic function where the leading coefficient is negative. In this case the arms of the graph will open down, then the maximum of the quadratic function coincides with the vertex of the function.
Where for a generic function:
y(x) = a*x^2 + b*x + c
The vertex is at:
x = -a/2b
and the maximum value is:
y(-a/2b)
Answer:
3.78
Step-by-step explanation:
Percentage solution with steps:
Step 1: We make the assumption that 9 is 100% since it is our output value.
Step 2: We next represent the value we seek with $x$.
Step 3: From step 1, it follows that $100\%=9$.
Step 4: In the same vein, $x\%=42$.
Step 5: This gives us a pair of simple equations:
$100\%=9(1)$.
$x\%=42(2)$.
Step 6: By simply dividing equation 1 by equation 2 and taking note of the fact that both the LHS
(left hand side) of both equations have the same unit (%); we have
$\frac{100\%}{x\%}=\frac{9}{42}$
Step 7: Taking the inverse (or reciprocal) of both sides yields
$\frac{x\%}{100\%}=\frac{42}{9}$
$\Rightarrow x=466.67\%$
Therefore, $42$ is $466.67\%$ of $9$.
I believe it's 15, but correct me if I'm wrong
This is because there is one 10 in 15. This gives you 3 tens and 5 in the ones.
X>-1/3, the graph would be filled everything to the right of -1/3 on the x axis
Answer:
1/16
Step-by-step explanation:
