Can you guys please help me? This is limited. (5v)^2/3 and the second one radical 10k

In ΔEFG, the measure of ∠G=90°, the measure of ∠E=6°, and GE = 71 feet. Find the length of EF to the nearest tenth of a foot.

djyliett [7]

Answer:68.2

Step-by-step explanation:

cos6=71/EF

cos6= 0.960170286650366

0.960170286650366= 71/EF

0.960170286650366*71=EF

EF= 68.2

3 0

3 years ago

Read 2 more answers

How do you use proportions to solve percent problems

exis [7]

Answer:

Step-by-step explanation:

EXAMPLE #1:

What number is 75% of 4? (or Find 75% of 4.)

The PERCENT always goes over 100.

(It's a part of the whole 100%.)

4 appears with the word of:

It's the WHOLE and goes on the bottom.

A proportion showing one fraction with PART as the numerator and 4 as the denominator equal to another fraction with 75 as the numerator and 100 as the denominator.

We're trying to find the missing PART (on the top).

In a proportion the cross-products are equal: So 4 times 75 is equal to 100 times the PART.

The missing PART equals 4 times 75 divided by 100.

(Multiply the two opposite corners with numbers; then divide by the other number.)

4 times 75 = 100 times the part

300 = 100 times the part

300/100 = 100/100 times the part

3 = the part

A proportion showing the denominator, 4, times the diagonally opposite 75; divided by 100.

7 0

3 years ago

Lowest common denominator of 3 5/7 and 4 4/5

IrinaK [193]

Answer: look at the screenshot

Step-by-step explanation:

it has everything you need

6 0

2 years ago

Please help with any of this Im stuck and having trouble with pre calc is it basic triogmetric identities using quotient and rec

german

How I was taught all of these problems is in terms of r, x, and y. Where sin = y/r, cos = x/r, tan = y/x, csc = r/y, sec = r/x, cot = x/y. That is how I will designate all of the specific pieces in each problem.

#3

Let's start with sin here. $\frac{2\sqrt{5}}{5} = \frac{2}{\sqrt{5}}$ Therefore, because sin is y/r, r = $\sqrt{5}$ and y = +2. Moving over to cot, which is x/y, x = -1, and y = 2. We know y has to be positive because it is positive in our given value of sin. Now, to find cos, we have to do x/r.

cos = $\frac{-1}{\sqrt{5}} = \frac{-\sqrt{5}}{5}$

#4

Let's start with secant here. Secant is r/x, where r (the length value/hypotenuse) cannot be negative. So, r = 9 and x = -7. Moving over to tan, x must still equal -7, and y = $4\sqrt{2}$ . Now, to find csc, we have to do r/y.

csc = $\frac{9}{4\sqrt{2}} = \frac{9\sqrt{2}}{8}$

The pythagorean identities are

sin^2 + cos^2 = 1,

1 + cot^2 = csc^2,

tan^2 + 1 = sec^2.

#5

Let's take a look at the information given here. We know that cos = -3/4, and sin (the y value), must be greater than 0. To find sin, we can use the first pythagorean identity.

sin^2 + (-3/4)^2 = 1

sin^2 + 9/16 = 1

sin^2 = 7/16

sin = $\sqrt{7/16}$ = $\frac{\sqrt{7}}{4}$

Now to find tan using a pythagorean identity, we'll first need to find sec. sec is the inverse/reciprocal of cos, so therefore sec = -4/3. Now, we can use the third trigonometric identity to find tan, just as we did for sin. And, since we know that our y value is positive, and our x value is negative, tan will be negative.

tan^2 + 1 = (-4/3)^2

tan^2 + 1 = 16/9

tan^2 = 7/9

tan = - $\sqrt{7/9} = \frac{-\sqrt{7}}{3}$

#6

Let's take a look at the information given here. If we know that csc is negative, then our y value must also be negative (r will never be negative). So, if cot must be positive, then our x value must also be negative (a negative divided by a negative makes a positive). Let's use the second pythagorean identity to solve for cot.

1 + cot^2 = $(\frac{-\sqrt{6}}{2})^{2}$

1 + cot^2 = 6/4

cot^2 = 2/4

cot = $\frac{\sqrt{2}}{2}$

tan = $\sqrt{2}$

Next, we can use the third trigonometric identity to solve for sec. Remember that we can get tan from cot, and cos from sec. And, from what we determined in the beginning, sec/cos will be negative.

$(\frac{2}{\sqrt{2}})^2$ + 1 = sec^2

4/2 + 1 = sec^2

2 + 1 = sec^2

sec^2 = 3

sec = - $\sqrt{3}$

cos = $\frac{-\sqrt{3}}{3}$

Hope this helps!! :)

3 0

2 years ago

Read 2 more answers

Which choice provides the most relevant detail?

aleksklad [387]

Option B, supplement and convert it into gas to use as fuel is the correct answer.

The best option is B because, compared to conventional yoghurt, Greek yoghurt demands up to four times as much milk to make. Greek yoghurt also generates more acid whey, that is challenging to dispose. During the production of yoghurt, a lot of gases are released along with the acid, which farmers have discovered can be utilized as a protein in livestock feed.

Additionally, scientists are attempting to reuse this acid. They are attempting to employ these pricey yet worthwhile conservation techniques. Nutritionists discuss Greek yogurt's advantages. As a result, choice B is correct.

Here is a similar question with an answer related to this question :

about whey: brainly.com/question/9171032

#SPJ4

7 0

2 years ago