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2 years ago

7

The difference of the sample means of two populations is 34.6, and the standard deviation of the difference of the sample means

is 11.9. The 95% confidence interval lies between A) -11.9 B) -23.8 C) -35.7 D) -45.4 and A) 11.9 B) 23.8 C) 35.7 D) 45.4

1 answer:

mojhsa [17]2 years ago

8 0

Answer

23.8,23.8

Step-by-step explanation:

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What is the solution of y − 4x = 0 and 3x + 6y = 9?

Elden [556K]

You solve this by plugging one equation into the other. Usually you have to rewrite one equation to make this work. In this case I choose to rewrite y-4x=0 as y=4x.

After plugging it into the second, you get:

3x + 6*4x = 9 => 27x = 9 => x=1/3

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3 years ago

Solve y'' + 10y' + 25y = 0, y(0) = -2, y'(0) = 11 y(t) = Preview

svetlana [45]

Answer: The required solution is

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$y^{\prime\prime}+10y^\prime+25y=0,~~~~~~~y(0)=-2,~~y^\prime(0)=11~~~~~~~~~~~~~~~~~~~~~~~~(i)$

Let us consider that

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Then, we have

$y^prime=me^{mt},~~~~~y^{\prime\prime}=m^2e^{mt}.$

Substituting these values in equation (i), we get

$m^2e^{mt}+10me^{mt}+25e^{mt}=0\\\\\Rightarrow (m^2+10y+25)e^{mt}=0\\\\\Rightarrow m^2+10m+25=0~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mt}\neq0]\\\\\Rightarrow m^2+2\times m\times5+5^2=0\\\\\Rightarrow (m+5)^2=0\\\\\Rightarrow m=-5,-5.$

So, the general solution of the given equation is

$y(t)=(A+Bt)e^{-5t}.$

Differentiating with respect to t, we get

$y^\prime(t)=-5e^{-5t}(A+Bt)+Be^{-5t}.$

According to the given conditions, we have

$y(0)=-2\\\\\Rightarrow A=-2$

and

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Thus, the required solution is

$y(t)=(-2+1\times t)e^{-5t}\\\\\Rightarrow y(t)=(-2+t)e^{-5t}.$

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2 years ago

Solve for x. Show each step of the solution.<br> Show each step when solving for x.

andrew-mc [135]

-3x(4-6x) < x+5

-12x+18x² < x+5

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3 years ago

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adelina 88 [10]

Answer:

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2 years ago