The length of DE is 39 and the length of EF is 36 because we can see from side AC and DF that triangle DEF is just triangle ABC dilated by 3.
X/5 + 3 = 2
x+15=10
x=-5
Ans : A
Domain = Set of all real numbers, which is choice B
Range = Choice C)

The domain is the set of allowed x value inputs of a function. In this case, we can plug in any x value we want. The graph stretches forever in both directions along the x axis. This is shown by the arrows.So that's why the domain is the set of all real numbers.
The range is the set of outputs of a function. It is the set of possible y values. As you can see on the graph, the highest point is at (-1,3) which is the vertex.
The largest y value possible is y = 3. Any other y value smaller than this is possible. So the range is therefore

where y is a real number
Not all prime numbers are odd, 2 is not odd and it's a prime number
Answer: A. "Segment AD bisects angle CAB." is the right answer.
Step-by-step explanation:
Given : In ΔABC ,AC≅AB.
⇒∠ACB=∠CBA....(1) (∵ angles opposite to equal sides of a triangle are equal )
Now in ΔACD and ΔABD
AD=AD (common)....(2)
Here we need one more statement to prove the triangles congruent that is only statement (A) fits in it.
If AD bisects ∠CAB then ∠CAD=∠BAD..(3)
Now again Now in ΔACD and ΔABD
∠ACB=∠CBA [from (1)]
AD=AD [common]
∠CAD=∠BAD [from (3)]
So by ASA congruency criteria ΔADC≅ΔABD.