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3 years ago

15

Two rectangles are similar. Rectangle ABCD has a length of 20 inches and width of 12 inches. Rectangle ABCD is dilated 25% of it

original size to form rectangle FGHJ. How is the area affected?

1 answer:

Solnce55 [7]3 years ago

7 0

FGHJ is 60 inches, because it was dilated 25%, and 25% of 240 is 60

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Griffins's driveway is 21 feet long.

elixir [45]

I believe multiply then 3

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2 years ago

Look at the figure. How can you prove the triangles are congruent?

jek_recluse [69]

Answer:

Δ ABD ≅ Δ CBD SSS

Step-by-step explanation:

AB ≅ CB Given

AD ≅ DC Given

BD ≅ BD Reflexive property

Δ ABD ≅ Δ CBD SSS

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2 years ago

6) The sum of three consecutive even numbers is 96.<br> What is the smallest of the three numbers ?

Neko [114]

Answer:

30

Step-by-step explanation:

Consecutive even numbers can be written as X,X+2,X+4,X+6, and so forth. You only have three consecutive even numbers that equal 96, so write the following equation:

X+X+2+X+4=96

1) Combine alike terms:

3X+6=96

2) Subtract 6 from both sides:

3X=90

3) Divide both sides by 3:

X=30

Now plug in 30 for each of the consecutive even numbers' equations:

X=30

X+2=32

X+4=34

The smallest of these three numbers is 30, therefore the answer is 30!

6 0

3 years ago

A cylindrical package with half a hemisphere to be sent by a postal service can have a maximum combined length (height of the cy

artcher [175]

Answer:

36 x 18 x 18

Step-by-step explanation:

By Lagrange multiplier's method,

∇f(x,y,z)= λ∇g(x,y,z) & g(x,y,z)=k

considering x,y,z as three unequal sides of the box

f(x,y,z)=xyz

If x represents the length, then constraint condition is g(x,y,z)= x + 2(y+z) =108

We have the following three equations:

yz= λ -->eq(1) fx= λgx

xz=2λ -->eq(2) fy=λgy

xy= 2λ -->eq(3) fz=λgz

x+2y+2z=108-->eq(4)

Dividing eq(2) by eq(1), we'll have

x / y =2

=> x= 2y

Also, by using eq(2)and eq(3), we can represent y=z

By substituting 'x= 2y' and 'y=z' in eq(4), we have

eq(4)=>

2y+ 2(y+y)= 108

y=108/6

y=18

<u>For x: </u> x=2y=> 2(18)=>36

<u>For z: </u>z= y = 18

Therefore, the dimensions are 36 x 18 x 18

5 0

3 years ago

Read 2 more answers

The dimensions of four rectangles are given below. Which has an area different from the area of each of the other three?

storchak [24]

To determine which of the rectangles has a different area, the areas of the four rectangles must be calculated. The rectangle with a different area is rectangle b

The dimension of the 4 rectangles are:

a. length: 4x and width: 4

b. length: 11 and width: x

c. length: 2 and width: 8x

d. length: 16x and width: 1

The area of a rectangle is:

$Area = Length \times Width$

<u>Rectangle (a)</u>

$Area = 4x \times 4$

$Area = 16x$

<u>Rectangle (b)</u>

$Area = 11 \times x$

$Area = 11x$

<u>Rectangle (c)</u>

$Area = 2 \times 8x$

$Area = 16x$

<u>Rectangle (d)</u>

$Area = 16x \times 1$

$Area = 16x$

Rectangles (a), (c) and (d) have the same area (i.e. 16x) while rectangle (b) has 11x as its area.

Hence, the rectangle with a different area is rectangle (b).

Read more about areas of rectangles at:

brainly.com/question/14383947

7 0

2 years ago