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spayn [35]
4 years ago
7

Please help with this. it wants to find M M

Mathematics
1 answer:
Lorico [155]4 years ago
3 0

Answer:

im so rorry i dont really understand it tho i could guess but i dont want you to get it wrong

Step-by-step explanation:

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Yeaaa I need help again. 1st pic should help you answer these questions (Questions are on the 2nd pic).
Liono4ka [1.6K]
Well ik the answer to number one is 180 bc it’s a straight line
4 0
3 years ago
Can someone please help me on a. and b.
Kitty [74]
A. 3,874 (Multiply 298 by 13.)

B. 46,488 (Multiply 3,874 by 12.)
8 0
3 years ago
Need help,please and thank you
kramer

So a complementary angle is going to equal 90 degrees.

The equation is : x - 10 + 4x - 10 = 90

Then, add together the matching terms : 5x - 20 = 90

Add 20 to both sides : 5x = 110

Then divide both sides by 5 : x = 22

Insert the value 22 into the first equation : (22 - 10) + (4*22 - 10) = 90

Solve : 12 + 78 = 90

Angle UVW = 12 and angle XYZ = 78

8 0
3 years ago
Use the definition of continuity to determine whether f is continuous at a. f(x) = 5x+5 a = -5 Question
Andrej [43]

ANSWER

lim_{x \to  - 5}(f(x))  = f( - 5)

EXPLANATION

If f(x) is continuous at

x = a

Then,

lim_{x \to a}(f(x))  = f(a)

The given function is

f(x) = 5x + 5

f( - 5) =  5( - 5) + 5

f( - 5) =  - 25 + 5 =  - 20

lim_{x \to  - 5}(f(x))  = 5( - 5) + 5

lim_{x \to  - 5}(f(x))  =  - 20

Since,

lim_{x \to  - 5}(f(x))  = f( - 5)

The function is continuous at

x =  - 5

4 0
3 years ago
Read 2 more answers
Suppose that ABCD is a trapezoid, with AB parallel to CD, and diagonals AC and BD intersecting at P. Explain why (a) triangles A
lora16 [44]

Answer:

A trapezoid ABCD is show below,

AB || CD

AC and BD are diagonals intersecting at P.

(a)

In Δ ABC and ABD,

Area of triangle ABC = Area of triangle ABD

Because,

Area of triangle ABC = 1/2 × Base × Height

Base = AB

Height = h, which is same for both the triangle that's why,

Area of triangle ABC = Area of triangle ABD

(b)

As we know that,

Area of triangle ABC = Area of triangle ABD

On subtracting the area of triangle ABP from both the triangles, we get

Area of triangle ABC - area of triangle ABP = Area of triangle ABD - area of triangle ABP

⇒ area of triangle BCP = area of triangle DAP

Hence, triangles BCP and DAP have the same area.

(c)

In triangle ABP and CDP,

∠ABP = ∠CDP (opposite interior angles are equal between two parallel lines)

∠APB = ∠CPD (opposite angles are equal)

∠BAP = ∠DCP (opposite interior angles are equal between two parallel lines)

Therefore,

By AAA similarity

Triangles ABP and CDP are similar.

(d)

In triangle BCP and DAP,

Only ∠BCP = ∠APD (opposite angles are equal).

Therefore,

Triangles BCP and DAP need not be similar.

8 0
3 years ago
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