First you plug in the missing values
y=3 x=4 z=2
3÷2×4-2
than you solve
the answer is 4
8x + 4 = 5x - 11
Subtract 5x from both sides:
3x + 4 = -11
Subtract 4 from both sides:
3x = -15
Divide both sides by 3:
x = -5
Answer : x = -5
Answer:
The drift angle is approximately 7.65° towards the East from the plane's heading
Step-by-step explanation:
The speed of the plane = 350 mph
The direction in which the plane flies N 40° E = 50° counterclockwise from the eastern direction
The speed of the wind = 40 mph
The direction of the wind = S 70° E = 20° clockwise from the eastern direction
The component velocities of the plane are;
= (350 × cos 50)·i + (350 × sin 50)·j
= (40 + cos 20)·i - (40 × sin 40)·j
The resultant speed of the plane = + = 265.915·i +242.404·j
The direction the plane is heading = tan⁻¹(242.404/265.915) ≈ 42.35°
Therefore, the drift angle = Actual Angle - Direction of the plane = 50 - 42.35 ≈ 7.65° towards the East
Answer:
A = 3.706 square meters
Step-by-step explanation:
the length of a cube has equal side.
therefore, the volume of a cube is given by S³
V = S³ = 7.14
where S is the length of a side
the surface area of a cube is = 6S²
where the area a aside is calculated, then it is multiply by 6.
if S³ = 7.14
S = ∛(7.14) = 1.925 m
What is the cross-sectional area that is parallel to one of its faces?
this is saying we should calculate for the cross-sectional area of one face. All faces in a cube is equal and parallel to each other.
the crossectional area of one side of a cube is = S² = 1.925² = 3.706 square meters
A = 3.706 square meters
