Answer:
31m/s
Step-by-step explanation:
Using the equation of motion
v² = u² + 2gH
H is the height of fall = 49m
g is the acceleration due to gravity = 9.8m/s²
u is the initial velocity = 0m/s
v² = 0² + 2(9.8)(49)
v² = 960.4
v = √960.4
v = 30.9m/s
v ≈ 31m/s
Hence the velocity of water at the turbine is 31m/s
Answer:
-2z+8
Step-by-step explanation:
Answer:
1250
Step-by-step explanation:
(2.5 • 100) • 5
Parentheses first
250 *5
1250
Set up:
(-32+8i)/(5+3i) * (5 - 3i)/(5-3i)
Keep in mind that i^2 = -1.
Take it from here.
12.29 is the square root of 151 to the nearest hundredth. It is about 12.28820572.