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Inga [223]
3 years ago
7

What is the Answer to this problem 75x+2=

Mathematics
1 answer:
pashok25 [27]3 years ago
4 0
75x+2=
75x-2=-2. move the 2 to the other side
75x=-2 now divide 75 both sides

75/75x=-2/75
x=-2/75
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How can you check that k ≥ 11 is the solution set to the inequality k + 14 ≥ 25?
Andreyy89

Answer:

K= 11

Step-by-step explanation:

You solve for K by subtracting 14 by 25.

25-14= 11

When k is pluged into k\geq 11 the statement is true because it is equal to 11.

When plugged into k+14\geq25;

11+14 =25.

That statement is also true because 25 is equel to 25.

8 0
3 years ago
What is 246000000 in standed form need to know whit in 15 min
11Alexandr11 [23.1K]

Answer:

2.46×10^8

Step-by-step explanation:

The decimal point is here

246000000.

Then it must be moved up to here

2.46000000

Those are eight steps from where it was, so to compensate and make sure the number remains the same remove the zeros and multiply by 10^8

Then you have

2.46×10^8

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3 years ago
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Answer:

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4 0
3 years ago
A rectangular prism has a length of 312 in., a width of 5 in., and a height of 112 in.
OLga [1]
Area of prism = area of base * height

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4 0
3 years ago
Which of the following is an equivalent equation obtained by completing the square of the expression below? x^2+6x−8=0 A (x+3)^2
valentina_108 [34]

Answer:

Solving the equation x^2+6x-8=0 by completing the square method we get \mathbf{(x+3)^2=17}

Option B is correct option.

Step-by-step explanation:

We need to solve the equation x^2+6x-8=0 by completing the square method.

For completing the square method: we need to follow: a^2+2ab+b^2=(a+b)^2

We are given:

x^2+6x-8=0

Solving by completing the square

x^2+2(x)(?)+(?)^2-8=0

We need to find ? in our case ? is 3 because 2*3= 6 and our middle term is 6x i,e 2(x)(3)=6x.

So, adding and subtracting (3)^2

x^2+2(x)(3)+(3)^2-8-(3)^2=0\\(x+3)^2-8-9=0\\(x+3)^2-17=0\\(x+3)^2=17

So, solving the equation x^2+6x-8=0 by completing the square method we get \mathbf{(x+3)^2=17}

Option B is correct option.

7 0
3 years ago
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