How much power is going through the out let <span />
The advantage of using a dynamic hard drive in a vm is that the space on the physical computer hard drive us used only when it's needed.
<h3>What is a virtual machine?</h3>
It should be noted that a virtual machine simply means a machine that allows one to run an operating system on your desktop.
The advantage of using a dynamic hard drive in a virtual machine is that the space on the physical computer hard drive us used only when it's needed.
Learn more about virtual machine on;
brainly.com/question/19743226
#SPJ12
Answer:
b. A global web of value creation activities
Explanation:
Multinational companies can benefit from creating a global network of value creation activities. With this strategy various phases of the value chain are distributed in several global locations where the cost of value creation is greatly reduced and value maximized. In this scenario Lenovo strategically chooses locations for the manufacturing of components for their ThinkPad laptops, while factoring costs involved and ensuring they are at a minimum. As with any strategy, it has its limitations that can reduce effectiveness such as trade barriers and other political risks.
Answer: provided in the explanation section
Explanation:
import java.util.*;
class Mutation {
public static int[] mutateTheArray(int n , int[] a)
{
int []b = new int[n];
for(int i=0;i<n;i++)
{
b[i]=0;
if(((i-1)>=0)&&((i-1)<n))
b[i]+=a[i-1];
if(((i)>=0)&&((i)<n))
b[i]+=a[i];
if(((i+1)>=0)&&((i+1)<n))
b[i]+=a[i+1];
}
return b;
}
public static void main (String[] args) {
Scanner sc = new Scanner(System.in);
int n= sc.nextInt();
int []a = new int [n];
for(int i=0;i<n;i++)
a[i]=sc.nextInt();
int []b = mutateTheArray(n,a);
for(int i=0;i<n;i++)
System.out.print(b[i]+" ");
}
}
cheers i hope this helped !!
The pseudocode :
Pair MaxiMini(array, sizeof_array)
if sizeof_array = 1
return element as both maximum and minimum
else if sizeof_array = 2
do one comparison to find the maximum and minimum
return that pair
else
# sizeof_array > 2
recursion for maximum and minimum of the left half
recursion for maximum and minimum of the right half
one comparison determines the true max of the two elements
one comparison determines the true min of the two elements
return the pair of maximum and minimum