Given:
Consider the below figure attached with this question.
To find:
The perimeter of the polygon UVWXYZ.
Solution:
All sides and vertical and horizontal. So, we can easily find the side lengths of the given polygon by counting the boxes between two points.
From the figure it is clear that,
UV = 9 units
VW = 2 units
WX = 3 units
XY = 3 units
YZ = 6 units
ZU = 5 units
Now, perimeter is the sum of all the sides.
Therefore, the perimeter of UVWXYZ is 28 units.
You put 4-3 over 7
4-3/7 = 1/7
So the answer would be 1/7
Answer:
4 seconds.
Step-by-step explanation:
The function f(x)=-10(x)(x-4) ........ (1), represents the approximate height of a projectile launch on the ground into the air as a function of time in seconds x.
Now, we are asked that for how long from the launch does the projectile stays in the air.
Therefore, we have to solve the equation (1) making f(x) as zero.
Hence, 10x(x - 4) = 0
⇒ x = 0 or x = 4
(As x can not be zero since at x = 0 sec, the projectile was at the ground.}
Hence, x = 4 seconds.
Therefore, the projectile was in the air for 4 seconds. (Answer)
We have
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A B C D E
-----------------------------------------------
1 yard
--------------
1/5 yard ------------------
7/10 yard
<span>The distance poles B and D= (1-1/5)=4/5 yard
</span>The distance poles B and E= BD+DE=4/5+7/10=(8+7)/10=15/10=3/2 yard
the answer is 3/2 yard (distance poles B and E)
