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Lilit [14]
3 years ago
9

Determine the standard form of the equation of the line that passes through (6,0) and (2,-7).

Mathematics
1 answer:
lesya [120]3 years ago
5 0

Answer:

-7x + 4y = +42

Step-by-step explanation:

Going from point (2, -7) to point (6, 0), x increases by 4 and y increases by 7.  Thus, the slope of the line in question is m = 7/4.

Starting from the equation y = mx + b, and subbing (7/4) for m, 6 for x and 0 for y, we get:

0 = (7/4)(6) + b.  Then b = 42/4, or 21/2.  Thus, we now have y = (7/4)x + 21/2.

We must put this into "standard form."  Multiplying all three terms by 4, we get:

4y = 7x + 42.  Rearranging these terms to fit the "standard form" equation Ax + By = C, we get:

-7x + 4y = +42

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Una heladeria dispone de 20 frutas distintas para elaborar sus malteadas. Si los clientes pueden elegir tres sabores para mezcla
Dahasolnce [82]

Answer:

Existen 6840 permitaciones de malteadas de tres sabores distintos que la heladería puede ofrecer.

Step-by-step explanation:

En este caso, el cliente que adquiere una malteada de tres sabores distintos sigue el siguiente procedimiento:

1) El primer sabor sale de cualquiera de las 20 frutas disponibles.

2) El segundo sabor es distinto al primer sabor, es decir, que sale de las 19 frutas restantes.

3) El tercer sabor es distinto al primer sabor y al segundo sabor, es decir, que sale de las 18 frutas restantes.

Puesto que existe una doble conjunción y que puede importar el orden según la preferencia del cliente, se habla matemáticamente de una permutación, definida como:

n\mathbb{P}k = \frac{n!}{(n-k)!} (1)

Donde:

n - Número de sabores disponibles, adimensional.

k - Número de sabores escogidos, adimensional.

Si tenemos que n = 20 y k = 3, entonces la cantidad de malteadas de tres sabores distintos es:

n\mathbb{P}k = \frac{20!}{(20-3)!}

n\mathbb{P}k = \frac{20!}{17!}

n\mathbb{P}k = 20\cdot 19\cdot 18

n\mathbb{P}k = 6840

Existen 6840 permitaciones de malteadas de tres sabores distintos que la heladería puede ofrecer.

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