Answer:
There are 1.05 x 10²⁴ molecules in 48.6 g N₂
Explanation:
1 mol of N₂ has a mass of (14 g * 2) 28 g.
Then, 48.6 g of N₂ will be equal to (48.6 g *(1 mol/ 28 g)) 1.74 mol.
Since there are 6.022 x 10²³ molecules in 1 mol N₂, there will be
(1.74 mol *( 6.022 x 10²³ / 1 mol)) 1.05 x 10²⁴ molecules in 1.74 mol N₂ (or 48. 6 g N₂).
Answer:
The turnover number is the maximum substrate quantitiy converted to product per enzyme and per second. It can be calculate as follows:
with
active enzyme concentration.
In this case we have Vmax an data to calculate ![[E]](https://tex.z-dn.net/?f=%5BE%5D)
![moles of E=\frac{10^{-9}g}{29600 g/mol}=3.38*10^{-14}](https://tex.z-dn.net/?f=moles%20of%20E%3D%5Cfrac%7B10%5E%7B-9%7Dg%7D%7B29600%20g%2Fmol%7D%3D3.38%2A10%5E%7B-14%7D)
Now
it is not like any option.
If we assume that
have the non usual units of
and it is ![6.8*10^-10 mol min^{-1}](https://tex.z-dn.net/?f=6.8%2A10%5E-10%20mol%20min%5E%7B-1%7D)
So we need divide by the moles of E (in place of [E])
Now ![k_c=\frac{6.8*10^-10}{3.38*10^{-14}}=20128 min^{-1} = 335 s{-1}](https://tex.z-dn.net/?f=k_c%3D%5Cfrac%7B6.8%2A10%5E-10%7D%7B3.38%2A10%5E%7B-14%7D%7D%3D20128%20min%5E%7B-1%7D%20%3D%20335%20s%7B-1%7D)
(pass from
to
dividing by 60)
<span>342.15g/mol I'm not for sure though </span>
Complete one rotation.
Hope this helps.
Answer:
hahahaa i can get the points
Explanation:
yes it is again LOL thanks