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padilas [110]
3 years ago
12

Sometimes a liquid can be sitting there and the molecules become gas. Thats called?

Chemistry
1 answer:
leva [86]3 years ago
8 0
It is called evaporation
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Use the rhombus to find the measure of the following angles m
Studentka2010 [4]

DA = 13, BW = 5, WC = 12, ∠ACD = 25°, ∠DAB = 50°, ∠ADC = 130°, ∠DBC = 65° and ∠BWC = 90° given that ABCD is a rhombus and DB = 10, BC = 13, ∠WAD = 25°. This can be obtained by understanding the properties of a rhombus.

<h3>What are the required values of sides and angles?</h3>

Here in the question it is given that,

  • ABCD is a rhombus
  • DB = 10, BC = 13, ∠WAD = 25°

We have to find the values of DA, BW, WC, ∠BAC, ∠ACD, ∠DAB, ∠ADC, ∠DBC, ∠BWC.

1) Since all the sides of the rhombus are equal, DA = 13

2) Since diagonals are perpendicular bisectors of each other, BW = 5

3) Since formula of diagonal is,

d₁ = √4a² - d₂,

here a = 13, d₂ = 10

d₁ = √4×13² - 10

d₁ = √676 - 10 = √576 = 24

Since diagonals are perpendicular bisectors of each other

WC = 24/2  ⇒ WC = 12

4) Since diagonals are angle bisectors at the corners, ∠BAC = 25°

5) Since diagonals are angle bisectors at the corners,

∠BAW = ∠DAW = 25° ⇒ ∠BAD =∠BAW + ∠DAW = 25° + 25° ⇒∠BAD = 50°

Since opposite angles of the rhombus are equal,

∠BAD = ∠BCD = 50° ⇒ ∠BCW = ∠DCW = 25°

⇒ ∠ACD = 25°

6) Since diagonals are angle bisectors at the corners,∠BAW = ∠DAW = 25° ⇒ ∠BAD =∠BAW + ∠DAW = 25° + 25° ⇒∠BAD = 50°

⇒ ∠DAB = 50°

7) Since adjacent angles are supplementary angles,

∠BAD + ∠ADC = 180° ⇒ 50° + ∠ADC = 180° ⇒ ∠ADC = 180° - 50° = 130°

⇒ ∠ADC = 130°

8) Since diagonals are angle bisectors at the corners,

∠DBC = 130°/2

⇒ ∠DBC = 65°

9) Since all the sides make an angle of 90° at the center,

⇒ ∠BWC = 90°

Hence DA = 13, BW = 5, WC = 12, ∠ACD = 25°, ∠DAB = 50°, ∠ADC = 130°, ∠DBC = 65° and ∠BWC = 90° given that ABCD is a rhombus and DB = 10, BC = 13, ∠WAD = 25°.

Learn more about rhombus here:

brainly.com/question/27870968

#SPJ9

6 0
2 years ago
The independent variable is the only factor that a scientist
Eva8 [605]
Changes. the dependent variable is affected by the independent variable
3 0
3 years ago
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How does the lens of a light microscope work?
ohaa [14]
D. the reflection of each concave lens makes the object appear larger
8 0
3 years ago
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Stoichiometry is best defined as the
Oxana [17]

Stoichiometry is “quantitative relationship” among the “reactants” and the “products” in a “chemical reaction”.

<u>Explanation</u>:  

In stoichiometry “stoicheion” means element and “metron” means measure in Greek. The stoichiometric calculation depends upon “stoichiometric coefficients” in a “chemical equation” which can be explained as the “number of moles” of each substance (reactants or products). Stoichiometric calculation is done as follows:

For example reaction between nitrogen and hydrogen to form ammonia as

\mathrm{N}_{2}(\mathrm{g})+3 \mathrm{H}_{2}(\mathrm{g}) \longrightarrow 2 \mathrm{NH}_{3}(\mathrm{g})

Here stoichiometric coefficients show that “one molecule of nitrogen” reacts with “three molecules of hydrogen” to form “two molecules of ammonia”. Multiplying Avogadro number 6.022 \times 10^{23} to no of molecules in equation:

\text { For } \mathrm{N}_{2}: 1 \times 6.022 \times 10^{23}=1 \mathrm{mol}

\text { For } 3 \mathrm{H}_{2}: 3 \times 6.022 \times 10^{23}=3 \mathrm{mol}

\text { For } 2 \mathrm{NH}_{3}: 2 \times 6.022 \times 10^{23}=2 \mathrm{mol}

Taking molar masses into consideration:  

\text { For } \mathrm{N}_{2}: 1 \times 28.0=28.0 \mathrm{gm}

\text { For } 3 \mathrm{H}_{2}: 3 \times 2=6.0 \mathrm{gm}

\text { For } 2 \mathrm{NH}_{3}: 2 \times 17=34 \mathrm{gm}

Hence balanced equation gives stoichiometric coefficients which gives proportion by moles.

8 0
3 years ago
Complete the mechanism for the electrophilic addition when the alkene is treated with water in acid.
s344n2d4d5 [400]

Answer:

CH₃CH == CH₂  +  H₂O → H⁺ →  CH₃CH(OH)CH₃  +  H⁺

The reaction of propene and water in acidic medium produces isopropyl alcohol.

Explanation:

Let's propose the following reaction:

Propene + H₂O in H⁺ medium  →  Alcohol

CH₃CH == CH₂  +  H⁺ →  CH₃C⁺CH₂

Electrons from the double bond attack the proton. So the double bond is broken and you form a carbocation.

Carbocation will be attacked by the electrons from the oxygen on the molecule of water.

CH₃C⁺CH₂  + H₂O: :  →  CH₃ _CH _ CH₃  

                                                   |

                                                ⁺OHH

It is called electrophilic addition cause the proton which is the electrophile is added to the sp₂ carbon in the alkene (where many H are bonded),  and the nucleophile, water is added to the other sp₂ carbon.

This last attack is so fast that the carbocation is combined with any nucleophile which it collides first. In the hydration reaction, there are two nucleophiles: water and the anion from the acid (let's think Cl⁻, cause our medium can be HCl).    The product of this collision is a protonated alcohol. Since we know that protonated alcohols are very strong acids, this protonated alcohol loses a proton, and the end product of the addition reaction is an alcohol.

In the first step, a proton adds to the alkene, but is returned to the reaction mixture during the final step, when the alcohol is deprotonated.

 CH₃ _CH _ CH₃   →   CH₃ _CH _ CH₃   + H⁺

             |                                 |

          ⁺OHH                          OH

         

           

3 0
3 years ago
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