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andreev551 [17]
3 years ago
8

"Construct a multistep synthetic route from ethylbenzene to (2-bromoethyl)benzene by dragging the appropriate items into the bin

s. Note that each bin will hold only one item, and not all reagents and structures will be used."

Chemistry
1 answer:
umka2103 [35]3 years ago
8 0

Answer:

The best reagents that are used for the conversion of ethylbenzene to (2-bromoethyl)benzene is shown in the first diagram attached.

Explanation:

Concepts and reason

The concept used to solve this problem is by using the given reagents, possible products will be formed in each step and then label it exactly in the given boxes in order to form the exact product.

Here, the starting reactant is ethyl benzene and the final product is (2-bromoethyl)benzene.

Fundamentals

Bromine molecule is used for bromination of alkene. Trans addition takes place.

Addition of HBr to the double bond forms an alkyl bromide.

Potassium tertiary butoxide is a sterically hindered base.

Bromination of alkane in the presence of sunlight gives radical substitution.

NBS (N-bromosuccinimide) is used for the allylic bromination.

The reaction is as shown in the second attachment(pictures 2,3 and 4).

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Determine the number of grams in each of the quantities<br><br> 1.39.0 x 1024 molecules Cl2
STatiana [176]

Mass of Cl₂ : 164.01 g

<h3>Further explanation</h3>

A mole is a number of particles(atoms, molecules, ions)  in a substance

This refers to the atomic total of the 12 gr C-12  which is equal to 6.02.10²³, so 1 mole = 6.02.10²³ particles  

Can be formulated :

N = n x No

N = number of particles

n = mol

No = 6.02.10²³ = Avogadro's number

mol Cl₂ :

\tt n=\dfrac{N}{No}\\\\n=\dfrac{1.39.10^{24}}{6.02.10^{23}}\\\\n=2.31

mass Cl₂(MW=71 g/mol) :

\tt mass=mol\times MW\\\\mass=2.31\times 71=164.01

8 0
3 years ago
Balance this chemical equation.
Vadim26 [7]

Answer:

Explanation:

Reaction Given

    NaHCO₃ (s) + HC₂H₃O₂ (aq) -------> CO₂ (g) + H₂O (l) + NaC₂H₃O₂ (aq)

Balance Equation = ?

Solution:

Balance Chemical Equation:

A balanced chemical equation is that in which the number of the reactant atoms equal to the number of the product atom.

For example if the carbon at the reactant side is 3, the number of carbon must be 3 on the product side.

Check the chemical equation and count the number of atoms at the reactant side and product side.

If the number of atoms of the reactants equal to the number of atoms of products then the reaction is balanced but if not equal then reaction is not balanced

Balancing is an trial and error process to get a balance reaction.

First we count the number of atoms of reactant and product

Number of atoms of Reactant:

Na = 1

O = 5

H = 5

C = 3

Number of atoms of Product:

Na = 1

O = 5

H = 5

C = 3

So this a balance equation as the atoms of the reactant atom equal to the number of the product atoms.

Na atom is 1 on both reactant and product side

Oxygen atoms are 5 on reactant and 5 on product side

hydrogen atoms are 5 on reactant and 5 on product side

Carbon atoms are 3 on reactant and 3 on product side

So all the compounds in the reaction have 1 as its coefficient in the blanks

<u />

<u>1   </u>NaHCO₃ (s) +  <u>1  </u>HC₂H₃O₂ (aq) -----> <u>1  </u>CO₂ (g) + <u>1  </u>H₂O (l) + <u>1  Na</u>C₂H₃O₂ (aq)

7 0
4 years ago
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