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Irina18 [472]
2 years ago
15

How do atoms explain the pattern that the mass of the products always equals the mass of the reaction?

Chemistry
1 answer:
galina1969 [7]2 years ago
7 0
The law of conservation of mass states that in a chemical reaction, the total mass of reactants is equal to the total mass of products. ... Because atoms are only rearranged in a chemical reaction, there must be the same number of sodium atoms and chlorine atoms in both the reactants and products.
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Which regions on the periodic table can adopt positive and negative oxidation numbers?
Dennis_Churaev [7]

<span>The region(s) of the periodic table which are made up of elements that can adopt both positive and negative oxidation numbers are the “non-metal” region. As we can see on the periodic table, the elements situated at the right side of the table have two oxidation states, one positive and the other a negative. </span>

7 0
3 years ago
How many liters of hydrogen are required to react completely with 2.4L of oxygen to form water? 2H2 + O2 --&gt; 2H2O
RoseWind [281]

Answer:

2.4 mole of oxygen will react with 2.4 moles of hydrogen

Explanation:

As we know

1 liter = 1000 grams

2H2 + O2 --> 2H2O

Weight of H2 molecule = 2.016 g/mol

Weight of water = 18.01 gram /l

2 mole of oxygen react with 2 mole of H2

2.4 mole of oxygen will react with 2.4 moles of hydrogen

3 0
2 years ago
1) Какое количество вещества Феррум (III) гидроксида вступает в реакцию с 15 г сульфатной кислоты?
EleoNora [17]

i dont speak russian sorry

3 0
3 years ago
How many moles are present in 4.7 liters of argon gas as STP
algol [13]
Answer:

0.21mol Ar (g)

Explanation:

To convert from litres to moles at STP we must divide the amount of litres by 22.4.

4.7 / 22.4 = 0.21mol Ar (g)
5 0
3 years ago
Read 2 more answers
A student heats a sample of hydrate once, and the mass of the sample and the evaporating dish is 16.428 g. After a second heatin
jolli1 [7]

Answer:

12.371 g

Explanation:

Given :

m_{evaporating\ dish}=1.135\ g

m_{evaporating\ dish}+m_{Hydrate\ sample}=25.637\ g

m_{evaporating\ dish}+m_{First\ heated\ sample}=16.428\ g

m_{evaporating\ dish}+m_{Second\ heated\ sample}=13.266\ g

Mass of salt hydrate:

m_{evaporating\ dish}=1.135\ g

m_{evaporating\ dish}+m_{Hydrate\ sample}=25.637\ g

m_{Hydrate\ sample}=25.637-m_{evaporating\ dish}\ g=25.637-1.135\ g=24.502\ g

Mass of salt anhydrous:

m_{evaporating\ dish}=1.135\ g

m_{evaporating\ dish}+m_{Second\ heated\ sample}=13.266\ g

m_{Second\ heated\ sample}=m_{salt\ anhydrous}=13.266-m_{evaporating\ dish}\ g=13.266-1.135\ g=12.131\ g

Mass of water:

m_{water}=m_{Hydrate\ sample}-m_{salt\ anhydrous}=24.502-12.131\ g=12.371\ g

m_{water}=12.371\ g

4 0
3 years ago
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