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3 years ago

Help asap pleaseeeee

Mathematics

1 answer:

gogolik [260]3 years ago

6 0

Answer:

i am usig this so i can figure it out ad edit it to the answer pls dont delete

Step-by-step explanation:

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Please answer need for geometry

IrinaK [193]

Answer:

d. 8.38 ft

Step-by-step explanation:

arc(NM) = 180° - 100° = 80° (Angles on a straight line)

Length of arc = θ/360°*2πr

θ = 80°

r = 6 ft

Plug in the values

Length of arc(NM) = 80/360*2*π*6

= 8.3775804

= 8.38 ft

7 0

2 years ago

Multiply or divide as indicated p^a*p^-3*p^2

Stella [2.4K]

Answer:

p^(a-1)

Step-by-step explanation:

The simplified expression can be seen in the picture attached below

As the factors have the same base, we just need to add or substract the exponents

p^(a-3+2) = p^(a-1)

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3 years ago

What is the Equation of the Line Passes through the points (-4,8) and (1,3)

Whitepunk [10]

Answer: y = –x + 4

Explanation:

8 0

3 years ago

An elementary school class ran 1 mile in an average of 11 minutes with a standard deviation of 3 minutes. Rachel, a student in t

Natali5045456 [20]

Answer:

a) Kenji's time had a lower z-score, which means that he is better compared to other runners on his level, and better to his peers compared to Nedda.

b) Rachel, because her time had the lowest z-score.

Step-by-step explanation:

Z-score:

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

The lower the time, the better the runner is. So whoever's time has a lower z-score is a better runner. So initially, we find the z-score of each student's time.

An elementary school class ran 1 mile in an average of 11 minutes with a standard deviation of 3 minutes. Rachel, a student in the class, ran 1 mile in 8 minutes.

This means that for Rachel's time, we have that $X = 8, \mu = 11, \sigma = 3$ . So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{8 - 11}{3}$

$Z = -1$

A junior high school class ran 1 mile in an average of 9 minutes, with a standard deviation of 2 minutes. Kenji, a student in the class, ran 1 mile in 8.5 minutes.

This means that for Kenji's time, we have that $X = 8.5, \mu = 9, \sigma = 2$ . So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{8.5 - 9}{2}$

$Z = -0.25$

A high school class ran 1 mile in an average of 7 minutes with a standard deviation of 4 minutes. Nedda, a student in the class, ran 1 mile in 8 minutes.

This means that for Nedda's time, we have that $X = 8, \mu = 7, \sigma = 4$ . So