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3 years ago

Three times a number x is at least -18

Mathematics

1 answer:

vladimir2022 [97]3 years ago

4 0

Answer:

$3x \geqslant - 18$

at least means it need to be more or the lowest it can be is 18

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The blade length is the radius of the circle formed by the area swept by the blades to the nearest square foot, what is the area

rewona [7]

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3 years ago

Read 2 more answers

Y is such that 4y _ 7<= 3y and 3y <= 5y +8. What range of values of y satisfies both inequalities

fgiga [73]

Answer:

Step-by-step explanation:

Given the inequality expressions

4y - 7 ≤ 3y and 3y≤5y+8

For 4y - 7 ≤ 3y

Collect like terms

4y - 3y ≤ 7

y ≤ 7

For 3y≤5y+8

Collect like terms

3y - 5y ≤ 8

-2y ≤ 8

y ≥ 8/-2

y ≥ -4

Combining both solutions

-4≤y≤7

<em>Hence the range of values of y that satisfies both inequalities is -4≤y≤7</em>

6 0

3 years ago

PLEASE HELP! YOU WILL GET 100 POINTS! SUPER CONFUSED NEED HELP AS SOON AS POSSIBLE THIS IS DUE SOON!!! QUESTION IN PICTURE BELOW

nekit [7.7K]

Answer:

Q = 40.6°

Explanation:

Given three sides: 9.6, 8.1, 6.3

Use the cosine rule:

c² = a² + b² - 2ab cos(C)

Insert following variables:

6.3² = 9.6² + 8.1² - 2(9.6)(8.1) cos(Q)

39.69 = 157.77 - 155.52 cos(Q)

cos(Q) = -118.08/-155.52

cos(Q) = 41/54

Q = cos⁻¹(41/54) = 40.6°

4 0

2 years ago

Determine the relationship between the two triangles and whether or not they can be

Digiron [165]

Answer:

congruent by side angle side so the triangle is congruent

7 0

3 years ago

Chose parameters h and k such that the system has a) a unique solution, b) many solutions, and c) no solution. 31+3x2= 4 2x1+kx2

Snezhnost [94]

Answer

a) k=7, h=9, the unique solution of the system is $(x_1,x_2)=(1,1)$

b) If k=6 and h=8 the system has infinite solutions.

c)If k=6 and h=9 the system has no solutions.

Step-by-step explanation:

I am assuming that the system is x1+3x2=4; 2x1+kx2=h

The augmented matrix of the system is $\left[\begin{array}{ccc}1&3&4\\2&k&h\end{array}\right]$ . If two times the row 1 is subtracted to row 2 we get the following matrix $\left[\begin{array}{ccc}1&3&4\\0&k-6&h-8\end{array}\right]$ .

Then

a) If k=7 and h=9, the unique solution of the system is $x_2=\frac{9-8}{7-6}=\frac{1}{1}=1$ and solviong for $x_1$ ,

$x_1+3x_2=4\\\\x_1=4-3(1)=1$

Then the solution is $(x_1,x_2)=(1,1)$

b) If k=6 and h=8 the system has infinite solutions because the echelon form of the matrix has a free variable.

c)If k=6 and h=9 the system has no solutions because the last equation of the system of the echelon form of the matrix is $0x_2=1$

8 0

3 years ago