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Kazeer [188]
3 years ago
8

Solve: z-5=75 A:z=71 B:z=80 C:z=70 D:z=79

Mathematics
2 answers:
ruslelena [56]3 years ago
7 0

Answer:

B.

Step-by-step explanation:

because 5 is taken away minus by 80.

poizon [28]3 years ago
5 0

B: z=80___________________________________

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Ted's second job offers 49,024 and it is 3819 greater than the first job

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The weekly demand for DVDs manufactured by a certain media corporation is given by
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Let <span>the production level that will yield a maximum profit for the manufacturer be x.
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Profit = Revenue - Cost = -0.0006x^3 + 65x - (-0.002x^2 + 13x + 4000) = -0.0006x^3 + 0.002x^2 + 52x - 4000

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3 years ago
In March there was 85 mm of rain. In April there was 68 mm. What is the percentage change?
ZanzabumX [31]
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Since 1936, the Gallup Organization has been asking Americans: "Are you in favor of the death penalty for a person convicted of
USPshnik [31]

Answer:

98% confidence interval for the proportion of all American females who support the death penalty for convicted murders is [0.59 , 0.64].

Step-by-step explanation:

We are given that the results of the most recent survey; in a sample of 3100 females, 62% said that they were in favor of the death penalty for convicted murders.

Firstly, the pivotal quantity for 98% confidence interval for the population proportion is given by;

                                 P.Q. =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of females who were in favor of the death penalty for convicted murders = 62%

n = sample of females = 3100

p = population proportion of all American females who support the death penalty

<em>Here for constructing 98% confidence interval we have used One-sample z proportion statistics.</em>

<u>So, 98% confidence interval for the population proportion, p is ;</u>

P(-2.33 < N(0,1) < 2.33) = 0.98  {As the critical value of z at 1% level

                                                   of significance are -2.33 & 2.33}  

P(-2.33 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 2.33) = 0.98

P( -2.33 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < {\hat p-p} < 2.33 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.98

P( \hat p-2.33 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < p < \hat p+2.33 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.98

<u>98% confidence interval for p</u> = [ \hat p-2.33 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } , \hat p+2.33 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ]

= [ 0.62-2.33 \times {\sqrt{\frac{0.62(1-0.62)}{3100} } } , 0.62+2.33 \times {\sqrt{\frac{0.62(1-0.62)}{3100} } } ]

 = [0.59 , 0.64]

Therefore, 98% confidence interval for the proportion of all American females who support the death penalty for convicted murders is [0.59 , 0.64].

4 0
2 years ago
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Answer:

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