Answer:
|x-3|-5
Step-by-step explanation:
f(x) = |x|
These lines are lines of absolute value equations. g(x) is shifted 3 units left so we subtract 3 from within the bars, and shifted down 5 units so we subtract 5 from the absolute value which leaves us with |x-3|-5
Answer:
f=16/7.3x
Step-by-step explanation:
Lets solve for f:
f(7.3)=16
Step 1:Divide both sides by 7.3x
7.3f/7.3x=16/17.3x
f=16/7.3x
Answer:
1/3
Step-by-step explanation:
Simplify the following:
((36/2)/(3×9))/2
((36/2)/(3×9))/2 = 36/(3×9×2×2):
36/(3×9×2×2)
36/9 = (9×4)/9 = 4:
4/(3×2×2)
4/2 = (2×2)/2 = 2:
2/(3×2)
2/(3×2) = 2/2×1/3 = 1/3:
Answer: 1/3
Answer:
<em>There are 72 crayons in the box</em>
Step-by-step explanation:
<u>Fractions</u>
To solve this problem we'll manage numbers as fractions to keep the precision up to the end of it.
Lynn has a box of crayons. It's given 4/9 of the crayons are blue. The remaining crayons are:
From that portion, 65% are red, or equivalently, 35% are yellow.
We write 35% as a fraction:
Thus, the portion of yellow crayons is:
This fraction of x crayons is equal to 14, thus:
x = 72
There are 72 crayons in the box
Answer:
0.347% of the total tires will be rejected as underweight.
Step-by-step explanation:
For a standard normal distribution, (with mean 0 and standard deviation 1), the lower and upper quartiles are located at -0.67448 and +0.67448 respectively. Thus the interquartile range (IQR) is 1.34896.
And the manager decides to reject a tire as underweight if it falls more than 1.5 interquartile ranges below the lower quartile of the specified shipment of tires.
1.5 of the Interquartile range = 1.5 × 1.34896 = 2.02344
1.5 of the interquartile range below the lower quartile = (lower quartile) - (1.5 of Interquartile range) = -0.67448 - 2.02344 = -2.69792
The proportion of tires that will fall 1.5 of the interquartile range below the lower quartile = P(x < -2.69792) ≈ P(x < -2.70)
Using data from the normal distribution table
P(x < -2.70) = 0.00347 = 0.347% of the total tires will be rejected as underweight
Hope this Helps!!!
