3 years ago

Please help geometry URGENT

Mathematics

1 answer:

rusak2 [61]3 years ago

4 0

Answer:

Step-by-step explanation:

$sin~\alpha =\frac{8}{17} \\cos~\alpha =\frac{15}{17} \\tan~\alpha =\frac{8}{15}$

You might be interested in

Solomon graphs a point on the coordinate plane. Which point did Solomon graph?

Mkey [24]

Answer:

Try your best! I know you can do it!

5 0

3 years ago

Theo had a balance of -$24 in his savings account. After making a deposit, he has $40 in his account. What is the overall change

never [62]

Answer:

Step-by-step explanation:

7 0

3 years ago

Help me to simplify; log_{5} 12.5+log_{5}10

liq [111]

Answer:

15.726

Step-by-step explanation:

log 5=0.698×12.5

=8.737

=0.698×10

=6.989

=8.737+6.989

=15.726

8 0

2 years ago

If m = 8, how many solutions are there to the expression 7m?

Mashutka [201]

Excchguvuvucucucucucuvihohojojohohphphphogoguretetwrqwwqqwwwesfxffcgvhbjb

3 0

3 years ago

Read 2 more answers

5 0 = - in = in quadrant II Given cos = Find sin 3

____ [38]

Answer:

sinΘ = $\frac{2}{3}$

Step-by-step explanation:

using the identity

sin²x + cos²x = 1 ( subtract cos²x from both sides )

sin²x = 1 - cos²x ( take square root of both sides )

sinx = ± $\sqrt{1-cos^2x}$

given

cosΘ = - $\frac{\sqrt{5} }{3}$ , then

sinΘ = ± $\sqrt{1-(-\frac{\sqrt{5} }{3})^2 }$

= ± $\sqrt{1-\frac{5}{9} }$

= ± $\sqrt{\frac{4}{9} }$

= ± $\frac{2}{3}$

since Θ is in quadrant II where sinΘ > 0 , then

sinΘ = $\frac{2}{3}$

7 0

2 years ago