All categories

3 years ago

Y=2/3(x-5)^2

Mathematics

1 answer:

Anvisha [2.4K]3 years ago

8 0

Answer:

see below

Step-by-step explanation:

The graph opens upward if the sign of the squared term is positive. If that sign is negative, the graph opens downward. The first three equations open upward; the last opens downward.

The line of symmetry is the value of x that makes the squared term zero. Here, that is x=5 for all equations.

y=2/3(x-5)^2: A, D

y=1/2(x-5)^2: A, D

y=3/4(x-5)^2: A, D

y=-4(x-5)^2: B, D

You might be interested in

18m + (-13m) = 25 m=

Levart [38]

Answer:

m=0

Step-by-step explanation:

i think?

7 0

2 years ago

Suppose a continuous probability distribution has an average of μ=35 and a standard deviation of σ=16. Draw 100 times at random

yulyashka [42]

Answer:

To use a Normal distribution to approximate the chance the sum total will be between 3000 and 4000 (inclusive), we use the area from a lower bound of 3000 to an upper bound of 4000 under a Normal curve with its center (average) at 3500 and a spread (standard deviation) of 160 . The estimated probability is 99.82%.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For sums, we have that the mean is $\mu*n$ and the standard deviation is $s = \sigma \sqrt{n}$

In this problem, we have that:

$\mu = 100*35 = 3500, \sigma = \sqrt{100}*16 = 160$

This probability is the pvalue of Z when X = 4000 subtracted by the pvalue of Z when X = 3000.

X = 4000

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{4000 - 3500}{160}$

$Z = 3.13$

$Z = 3.13$ has a pvalue of 0.9991

X = 3000

$Z = \frac{X - \mu}{s}$

$Z = \frac{3000 - 3500}{160}$

$Z = -3.13$

$Z = -3.13$ has a pvalue of 0.0009

0.9991 - 0.0009 = 0.9982

So the correct answer is:

5 0

3 years ago

Can anyone solve this?

Serhud [2]

Answer:

A) 96 cm

Step-by-step explanation:

Split into three parallelograms

Shape 1: 6 by 7 6×7=42

Shape 2: 3 by 4 3×4=12

Shape 3: 6 by 7 6×7=42

42+12+42=96

6 0

2 years ago

Read 2 more answers

How much change will you get back if you bought three 0.78 chocolate bars and paid with a $5 bill?

Hitman42 [59]

2 dollars and 66 cents

4 0

2 years ago

Read 2 more answers

Math Question: Pls help I will do anything

kow [346]

Answer:

The probability of spinning red is $\frac{1}{3}$ , the probability of spinning a 1 is $\frac{1}{6}$ , the probability of spinning an odd number is $\frac{1}{2}$ , and the probability of spinning a 9 is 0.

Step-by-step explanation:

Since there are a total of 6 possible outcomes, you can use this in the following questions. There are 2 red tiles, so the probability of spinning red is $\frac{2}{6}$ or $\frac{1}{3}$ . Since there are only one 1 tile, the probability of spinning a 1 is $\frac{1}{6}$ . Since there are three odd numbers, the probability of spinning an odd number is $\frac{1}{2}$ . Since there are no 9 in the spinner, the probability of spinning a 9 is 0 or never.

5 0

2 years ago