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victus00 [196]
3 years ago
6

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Mathematics
2 answers:
olga nikolaevna [1]3 years ago
8 0
<h3>Answer:   1.15</h3>

==============================================================

Work Shown:

QR = 73

QP = 55

PR = x

Pythagorean Theorem

a^2 + b^2 = c^2

(QP)^2 + (PR)^2 = (QR)^2

(55)^2 + (x)^2 = (73)^2

3025 + x^2 = 5329

x^2 = 5329-3025

x^2 = 2304

x = sqrt(2304)

x = 48

PR = 48

----------

tan(angle) = opposite/adjacent

tan(R) = QP/PR

tan(R) = 55/48

tan(R) = 1.1458333 approximately

tan(R) = 1.15

Alexxx [7]3 years ago
8 0

Answer:

0.75°

Step-by-step explanation:

tan< R= 55÷73

=0.75

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triangle AMY ~ MEG , AM = 5 MY=7 AY =3. MEG IS A DILATION of AMY by a scale facyor of 1/3. fimd the perimeter of MEG.
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Answer:

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From the question, we're told that triangles AMY and MEG are similar. If triangle AMY has sides AM = 5, MY = 7, and AY = 3 then we can find the side lengths of triangle MEG since we're told from the question that it is a dilation of AMY by a scale factor of 1/3.

So all we need to is multiply the corresponding sides of AMY by 1/3, so we'll have;

\begin{gathered} ME=5\ast\frac{1}{3}=\frac{5}{3} \\ EG=7\ast\frac{1}{3}=\frac{7}{3} \\ MG=3\ast\frac{1}{3}=3 \end{gathered}

We can then go ahead and find the perimeter of MEG. Note that to find the perimeter of a triangle, we add all the length of its sides;

\begin{gathered} \text{Perimeter of MEG}=\frac{5}{3}+\frac{7}{3}+3 \\ =\frac{5+7+9}{3} \\ =\frac{21}{3} \\ =7 \end{gathered}

The perimeter of MEG is 7.

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