Answer:
so first get your calc out and type in the formula once you do that but 16 times 7 and equal it than divide it and tell me what you get
Step-by-step explanation:
Answer:
ба ман нуқтаҳо лозиманд :) умедворам шумо мефаҳмед
Step-by-step explanation:
<span>For this case we have the following expression:
</span>
![\frac{n ^ 4-11n ^ 2 + 30}{ n ^ 4-7n ^ 2 + 10} ](https://tex.z-dn.net/?f=%20%5Cfrac%7Bn%20%5E%204-11n%20%5E%202%20%2B%2030%7D%7B%20n%20%5E%204-7n%20%5E%202%20%2B%2010%7D%20%0A%0A)
<span> We are going to make the following change of variables:
</span>
![x = n ^ 2 ](https://tex.z-dn.net/?f=x%20%3D%20n%20%5E%202%0A)
<span>Rewriting the expression we have:
</span>
![\frac{(x ^ 2-11x + 30)}{(x ^ 2-7x + 10)} ](https://tex.z-dn.net/?f=%20%5Cfrac%7B%28x%20%5E%202-11x%20%2B%2030%29%7D%7B%28x%20%5E%202-7x%20%2B%2010%29%7D%20%0A%0A)
<span>Factoring the expression we have:
</span>
![\frac{(x-5) (x-6)}{(x-5) (x-6)} ](https://tex.z-dn.net/?f=%20%5Cfrac%7B%28x-5%29%20%28x-6%29%7D%7B%28x-5%29%20%28x-6%29%7D%20%0A)
<span>Canceling similar terms we have:
</span>
![\frac{x-6}{x-2} ](https://tex.z-dn.net/?f=%20%5Cfrac%7Bx-6%7D%7Bx-2%7D%20%0A)
<span>Returning the change we have:
</span>
![\frac{n ^ 2-6}{n ^ 2-2} ](https://tex.z-dn.net/?f=%20%5Cfrac%7Bn%20%5E%202-6%7D%7Bn%20%5E%202-2%7D%20%0A%0A)
<span> The resctrictions of the function are those that make the denominator equal to zero.
We have then:
</span>
![n ^ 2-2 = 0 n = +/- \sqrt{2} ](https://tex.z-dn.net/?f=n%20%5E%202-2%20%3D%200%0A%0An%20%3D%20%2B%2F-%20%20%5Csqrt%7B2%7D%20%0A)
<span>
Answer: The simplified expression is: </span>
<span>
The restrictions are: </span>
C.) 5, Using P.E.M.D.A.S you have to multiply first, so replacing the variable X with 5, it should look like this: (6*5) -3=27. 6*5 is 30, 30 subtracted by 3 is 27.
Answer:
<h2>c. 16.5</h2>
Step-by-step explanation:
It's the right triangle.
The formula of an area of a right triangle:
![A=\dfrac{(leg)(leg)}{2}](https://tex.z-dn.net/?f=A%3D%5Cdfrac%7B%28leg%29%28leg%29%7D%7B2%7D)
Look at the picture.
We have
![leg=3,\ leg=11](https://tex.z-dn.net/?f=leg%3D3%2C%5C%20leg%3D11)
Substitute:
![A=\dfrac{(3)(11)}{2}=\dfrac{33}{2}=16.5](https://tex.z-dn.net/?f=A%3D%5Cdfrac%7B%283%29%2811%29%7D%7B2%7D%3D%5Cdfrac%7B33%7D%7B2%7D%3D16.5)