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Evgesh-ka [11]
2 years ago
8

Solve for x. 5x/−6 = −40/3 Enter your answer in the box

Mathematics
2 answers:
eduard2 years ago
8 0

Answer:

x = 16

That's your answer

Crank2 years ago
3 0

Answer:

5x/_6 =_40/3(cross product)

after,15x/15=240/15

x=16

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Step-by-step explanation:

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3 years ago
5x + 9 = 5 + 3x : solve
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5x - 9 = 5 - 3x

5x - 3x = 5 - 9

2x = -4

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5 0
3 years ago
Help i made it worth a lot of points
raketka [301]

Answer:

36x^6/y^10

Step-by-step explanation:

First evaluate the parentheses, 6x^3 x 6x^3 = 36x^6

y^5 x y^5 = y^10 ; remember m^k x m^r = m^k+r

final answer should be 36x^6/y^10

hope this helps :')

4 0
2 years ago
Read 2 more answers
Make a table of ordered pairs for the equation.
soldier1979 [14.2K]
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4 0
3 years ago
PLEASE HELP I NEED THIS ASAP<br> Find the vertex of y=x^2-7x+4
Goshia [24]

Answer:

\mathrm{Minimum}\space\left(\frac{7}{2},\:-\frac{33}{4}\right)

Step-by-step explanation:

y=x^2-7x+4\\\mathrm{The\:vertex\:of\:an\:up-down\:facing\:parabola\:of\:the\:form}\:y=ax^2+bx+c\:\mathrm{is}\:x_v=-\frac{b}{2a}\\\mathrm{The\:parabola\:params\:are:}\\a=1,\:b=-7,\:c=4\\x_v=-\frac{b}{2a}\\x_v=-\frac{\left(-7\right)}{2\cdot \:1}\\\mathrm{Simplify}\\x_v=\frac{7}{2}\\\mathrm{Plug\:in}\:\:x_v=\frac{7}{2}\:\mathrm{to\:find\:the}\:y_v\:\mathrm{value}\\y_v=\left(\frac{7}{2}\right)^2-7\cdot \frac{7}{2}+4\\

\mathrm{Simplify\:}\left(\frac{7}{2}\right)^2-7\cdot \frac{7}{2}+4:\quad -\frac{33}{4}\\y_v=-\frac{33}{4}\\Therefore\:the\:parabola\:vertex\:is\\\left(\frac{7}{2},\:-\frac{33}{4}\right)\\\mathrm{If}\:a0,\:\mathrm{then\:the\:vertex\:is\:a\:minimum\:value}\\a=1\\\mathrm{Minimum}\space\left(\frac{7}{2},\:-\frac{33}{4}\right)

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