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kenny6666 [7]
3 years ago
6

If f(x) = 4 – x2 and g(x) = 6x, which expression is equivalent to (g – f)(3)?

Mathematics
2 answers:
Murljashka [212]3 years ago
4 0
F(x) = 4 - x²    Df: x∈R

g(x) = 6x  Dg: x∈R

Df = Dg therefore (g - f)(x) = g(x) - f(x)

(g - f)(3) = g(3) - f(3)

subtitute the value of x to equations:

g(3) = 6 · 3 = 18
f(3) = 4 - 3² = 4 - 9 = -5

(g - f)(3) = 18 - (-5) = 18 + 5 = 23

NNADVOKAT [17]3 years ago
3 0
f(x) = -x^2 + 4

g(x) = 6x

(g - f)(3) = 6(3) - (-(3)^2 + 4)

(g - f)(3) = 18 - (-9 + 4) 

(g - f)(3) = 18 - (-5)

(g - f)(3) = 18 + 5

(g - f)(3) = 23
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MrMuchimi

Answer:

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