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Ivanshal [37]
3 years ago
13

Expand to write and equivalent expression: 4/5(5k-12d)

Mathematics
1 answer:
yawa3891 [41]3 years ago
4 0

Answer:

4k-9 3/5d

hope this helps

have a good day :)

Step-by-step explanation:

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Solve and check:8a-4=25+6(a-8)
OlgaM077 [116]
8a - 4 = 25 + 6 (a - 8)

(distribute the 6)

8a - 4 = 25 + 6a - 48

(combine like terms 25 - 48)

8a - 4 = 6a - 23

( subtract 6a from both sides)

2a - 4 = -23

(add 4 to both sides)

2a = -19

(divide both sides by 2)

a = - 9.5

////CHECK/////

8 (-9.5) - 4 = 25 + 6 ( -9.5 -8)

(plug each side into a calculator)

-80 = -80

FINAL ANSWER:

a = -9.5
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Nial is signing a lease for an apartment that rents for $1020/month. How much will he pay to move in if he must pay the first an
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A manufacturer of golf equipment wishes to estimate the number of left-handed golfers. A previous study indicates that the propo
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Answer:

A sample of 997 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

The margin of error is of:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

A previous study indicates that the proportion of left-handed golfers is 8%.

This means that \pi = 0.08

98% confidence level

So \alpha = 0.02, z is the value of Z that has a p-value of 1 - \frac{0.02}{2} = 0.99, so Z = 2.327.  

How large a sample is needed in order to be 98% confident that the sample proportion will not differ from the true proportion by more than 2%?

This is n for which M = 0.02. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.02 = 2.327\sqrt{\frac{0.08*0.92}{n}}

0.02\sqrt{n} = 2.327\sqrt{0.08*0.92}

\sqrt{n} = \frac{2.327\sqrt{0.08*0.92}}{0.02}

(\sqrt{n})^2 = (\frac{2.327\sqrt{0.08*0.92}}{0.02})^2

n = 996.3

Rounding up:

A sample of 997 is needed.

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